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Alex73 [517]
3 years ago
13

A fruit company recently released a new applesauce. By the end of its first​ year, profits on this product amounted to $ 35 comm

a 900.$35,900. The anticipated profit for the end of the fourth year is $ 44 comma 300.$44,300. After the first​ year, the ratio of change in time to change in profit is constant. Let x be years and P be profit in dollars. A. Write a linear function​ P(x) that expresses profit as a function of time.
Mathematics
1 answer:
Vikki [24]3 years ago
3 0

Answer:

P(x) = 35,900 + 2,800(x-1)

Step-by-step explanation:

P(x)

P(1) = $35,900

P(4) = $44,300

Difference in profits

P(4) - P(1)

= P(3)

= $44,300 - $35,900

= $8,400

Rate of change per year = $8,400 / 3

= $2,800 per year

The linear equation

P(x) = 35,900 + 2,800(x-1)

Where

x = number of years

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fgiga [73]

Step-by-step explanation:

Given:

Mean = 33700

Median = 34600

Mode = 35600

The mean is the average, the median is the middle number, and the mode is the most common number.

a)

First, we need to find the new mean (average) if one of the employees gets a 3500 raise.  The average is the total salary divided by number of employees:

(5 × 33700 + 3500) / 5 = 34400

b)

The mode is the most common number in a set.  Since there are only five employees, and the mode is different than the median, then the two highest earners must have the same salary.  The salaries from smallest to largest is therefore:

?, ?, 34600, 35600, 35600

When the median gets the 3500 raise, the set becomes:

?, ?, 35600, 35600, 38100

So the new median is 35600.

c)

The most common number is still 35600.  So the mode hasn't changed: 35600.

4 0
3 years ago
A parking lot contains 100 cars , k of which happen to be lemons. we select m of these cars
Sunny_sXe [5.5K]
Given that a parking lot contains 100 cars, k of which happen to be lemons.

This is a conditional probability question.

Let event A be that a car is tested and event B be that a car is lemon.

The probability that a car is lemon is given by \frac{k}{100}

The probability that a car is tested is given by \frac{m}{100}

The probability that a car is lemon and it is tested is given by \frac{n}{m}

For a conditional probability, the probablility of event A given event B is given by:

P(A|B)= \frac{P(A\cap B)}{P(B)}

Therefore, the probability that a car is lemon, given that it is tested is given by.

P(lemon|tested)= \frac{P(lemon\, and\, tested)}{P(tested)}  \\  \\ = \frac{ \frac{n}{m} }{ \frac{m}{100} } = \frac{n}{m} \times \frac{100}{m} = \frac{100n}{m^2}
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3 years ago
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lutik1710 [3]

Answer:

Step-by-step explanation:

Given the expression cosec (x) = 4 and tan(x)< 0

since cosec x = 1/sinx

1/sinx = 4

sinx = 1/4

From SOH, CAH TOA

sinθ = opposite/hypotenuse

from sinx = 1/4

opposite = 1 and hypotenuse = 4

to get the adjacent, we will use the Pythagoras theorem

adj² = 4²-1²

adj² = 16-1

adj ²= 15

adj = √15

cosx = adj/hyp = √15/4

tanx = opposite/adjacent = 1/√15

since tan < 0, then tanx = -1/√15

From double angle formula;

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sin2x = 2√15/16

sin2x = √15/8

for cos2x;

cos2x = 1-2sin²x

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cos2x = 1-2(1/16)

cos2x= 1-1/8

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tan2x  = tanx + tanx/1-tan²x

tan2x = 2tanx/1-tan²x

tan2x = 2(-1/√15)/1-(-1/√15)²

tan2x = (-2/√15)/(1-1/15)

tan2x = (-2/√15)/(14/15)

tan2x = -2/√15 * 15/14

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rationalize

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tan2x =  -30√15/7*15

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Answer:

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