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natta225 [31]
3 years ago
13

Please answer this I really need help, Ariel spent a total of $3.42 buying dried apricots from the bulk bins, which were on sale

for $2.85 per pound. To the nearest tenth of a pound, how many pounds of dried apricots did Ariel buy?
A.0.8
B.0.6
C.1.2
D.6.0
Mathematics
1 answer:
Kamila [148]3 years ago
5 0

Answer:

1.2 lbs

Step-by-step explanation:

This problem is set up so that the total price is proportional to the price per pound, so to find the proportion you would divide the total cost by the cost per pound. 3.42/2.85 = 1.2, so the answer is 1.2 pounds.

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How do I Simplify this fraction <br><br> 4/5
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Answer:

you don't, the fraction \frac{4}{5}  

or 4/5

is already in its simplest form.

Step-by-step explanation:

if you want it as a decimal, simply divide.

numerator by the denominator

4 divided by 5

which is 0.8  

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3 years ago
Good morning can y’all help me
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Answer:

The answer is (A.)

Step-by-step explanation:

4 x 9 = 36

6 x 9 = 54

8 x 9 = 72

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What is the answer to 3x=-3x-6
ahrayia [7]

Answer:

x=-1

Step-by-step explanation:

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3 years ago
Read 2 more answers
These are the last two questions on my math homework, please help!
liraira [26]

Answer:

A rectangular Prism

52 square units

Step-by-step explanation:

3*4= 12*2= 24

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3 0
3 years ago
Tourism is extremely important to the economy of Florida. Hotel occupancy is an often-reported measure of visitor volume and vis
docker41 [41]

Answer:

Explained below.

Step-by-step explanation:

In this case we need to determine if there has been an increase in the proportion of rooms occupied over the one-year period.

(a)

The hypothesis can be defined as follows:  

<em>H</em>₀: The proportion of rooms occupied over the one-year period has not increased, i.e. <em>p</em>₁ - <em>p</em>₂ ≤ 0.  

<em>Hₐ</em>: The proportion of rooms occupied over the one-year period has increased, i.e. <em>p</em>₁ - <em>p</em>₂ > 0.  

(b)

The information provided is:

n₁ = 1750

n₂ = 1800

X₁ = 1470

X₂ = 1458

Compute the sample proportions and total proportions as follows:

 \hat p_{1}=\frac{X_{1}}{n_{1}}=\frac{1470}{1750}=0.84\\\\\hat p_{2}=\frac{X_{2}}{n_{2}}=\frac{1458}{1800}=0.81\\\\\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{1470+1458}{1750+1800}=0.825

(c)

Compute the test statistic value as follows:

Z=\frac{\hat p_{1}-\hat p_{2}}{\sqrt{\hat p(1-\hat p)\times [\frac{1}{n_{1}}+\frac{1}{n_{2}}]}}

   =\frac{0.84-0.81}{\sqrt{0.825(1-0.825)\times [\frac{1}{1750}+\frac{1}{1800}]}}\\\\=2.352

The test statistic value is 2.352.

(d)

The decision rule is:

The null hypothesis will be rejected if the p-value of the test is less than the significance level.

Compute the p-value as follows:

 p-value=P(Z>2.352)=1-P(Z

The p-value of the test is very small. The null hypothesis will be rejected at any significance level.

Thus, there enough evidence suggesting that there has been an increase in the proportion of rooms occupied over the one-year period.

7 0
3 years ago
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