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yaroslaw [1]
3 years ago
6

Help please :( thank u

Mathematics
1 answer:
snow_tiger [21]3 years ago
8 0

Answer:

he needs to know the width!!!

Step-by-step explanation:

since length multiplied by the width equals area,

so since the length is given, the width is needed

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What is the value of the arithmetic series below?
RoseWind [281]

Answer:

- 494

Step-by-step explanation:

Breaking down the summation into it;s component parts

= 4k - \frac{3}{2} k(k + 1) ← substitute k = 19

= (4 × 19 ) - 1.5 × (19 × 20)

= 76 - (1.5 × 380)

= 76 - 570

= 494

3 0
3 years ago
Read 2 more answers
Let v⃗ 1=⎡⎣⎢033⎤⎦⎥,v⃗ 2=⎡⎣⎢1−10⎤⎦⎥,v⃗ 3=⎡⎣⎢30−3⎤⎦⎥ be eigenvectors of the matrix A which correspond to the eigenvalues λ1=−1, λ2
kaheart [24]

Answer:

- x as a linear combination :

x = -1 v1+ 0 v2+ 1 v3.

- Transpose Ax = (12, -6, -6)

Step-by-step explanation:

Given v1 = (0 3 3),v2 = (1 −1 0), v3 = (3 0 −3) be eigenvectors of the matrix A which correspond to the eigenvalues λ1 = −1, λ2 = 0, and λ3 = 1, respectively, and let x = (−2 −4 0). Express x as a linear combination of v1, v2, and v3, and find Ax .

To write x as a linear combination of v1, v2, and v3

x = -1 v1+ 0 v2+ 1 v3.

To find Ax

Write A = (0 ......3 ......3 )

...................(1 ......-1 ......0)

...................(3 ......0......-3)

Since transpose x = (-2, 4, 0)

Ax =......... (0 ......3......3 )(-2)

...................(1 ......-1 ......0)(4)

...................(3 ......0......-3)(0)

= (0×-2 + 3×4 + 3×0)

...(1×-2 + -1×4 + 0×0)

.. (3×-2 + 0×4 + -3×0)

As = (12)

....(-6)

....(-6)

Transpose Ax = (12, -6, -6)

7 0
3 years ago
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k0ka [10]
Jim has 27.5 minutes left to get to the airport.
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Consider the function given below.
MAVERICK [17]
You have to put a picture of the problem
3 0
3 years ago
A set of 12 windup toys costs $9. What is the cost per windup toy?
-BARSIC- [3]

Answer:

0.75

Step-by-step explanation:

9 ÷ 12 = 0.75

hope this helps...

4 0
3 years ago
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