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kicyunya [14]
3 years ago
10

PLS HELP WILL MARK BRAINLEST IF UR CORRECT

Mathematics
2 answers:
zubka84 [21]3 years ago
8 0

Answer:

52. (0,-3)

53. Slope= 4

54. Y=4x-3

12345 [234]3 years ago
3 0
I think it’s a carrot
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Name the different types of proofs you saw in this lesson. Give a description for each.
seraphim [82]

Answer:

?

Step-by-step explanation:

4 0
3 years ago
Solve the following <br> -5x + 3 = 2x - 1
skelet666 [1.2K]

x=4/7

Step-by-step explanation:

get x alone.

1st get 3 on the other side of the = sign by using the opposite sign. the opposite of addition is subtraction

-5x+3=2x-1

-3 -3

-5x=2x-1-3

-5x=2x-4

now we get the xs together. the opposite of addition( the 2 is positive) is subtraction

-5x=2x-4

-2x -2x

-7x=-4

now let's get the -7 out of here. -7 is multiplying by x. the opposite of multiplication is division.

<u>-7x</u><u> </u>= <u>-</u><u>4</u>

-7. -7

x=-4/-7

negative divided by a negative is a positive

x=4/7

5 0
2 years ago
At a college campus, random drug tests are carried out to prevent use of prohibited drugs by athletes. Of all the athletes on ca
saw5 [17]

Answer:

a) 0.3064 = 30.64% probability that athlete will test positive for prohibited drug use.

b) 0.2693 = 26.93% probability that this drug user never used the prohibited drug.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

A. If an athlete is selected at random, what is the probability that athlete will test positive for prohibited drug use?

100 - 5 = 95% of 8%

100 - 13 = 87% of 17%

11% of 75%

So

p = 0.95*0.08 + 0.87*0.17 + 0.11*0.75 = 0.3064

0.3064 = 30.64% probability that athlete will test positive for prohibited drug use.

B. If an athlete tests positive after a drug test, what is the probability that this drug user never used the prohibited drug?

Conditional Probability

Event A: Tests Positive

Event B: Never used the drug.

0.3064 = 30.64% probability that athlete will test positive for prohibited drug use

This means that P(A) = 0.3064

Probability of testing positive while never using the drug.

11% of 75%. So

P(A \cap B) = 0.11*0.75 = 0.0825

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0825}{0.3064} = 0.2693

0.2693 = 26.93% probability that this drug user never used the prohibited drug.

8 0
3 years ago
During 2021, equipment was sold for $470000. The equipment cost $782000 and had a book value of $439000. Accumulated Depreciatio
algol [13]

Answer:

$149,000

Step-by-step explanation:

Subtract acc depreciation for 2020 from acc deprecitation in 2021 and it gives you the depreciation expense solely for 2021.

4 0
3 years ago
If quadrilateral PQRS is a kite, which statements must be true? Check all that apply.
mel-nik [20]

A kite is a quadrilateral in which two disjoint pairs of consecutive sides are congruent (“disjoint pairs” means that one side can’t be used in both pairs).

Then:

  • Two disjoint pairs of consecutive sides are congruent by definition - QP≅QR and QR is not congruent to RS (one side can’t be used in both pairs);
  • One diagonal (segment QS, the main diagonal) is the perpendicular bisector of the other diagonal (segment PR, the cross diagonal), so PM≅MR;
  • The opposite angles at the endpoints of the cross diagonal are congruent, thus ∠QPS≅∠QRS.
  • ∠PQR is not congruent to ∠PSR, because they are not angles at the endpoints of the cross diagonal.

Answer: correct options are A, B and E.

3 0
4 years ago
Read 2 more answers
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