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likoan [24]
3 years ago
13

Aqueous calcium bromide was mixed with aqueous gold(i perchlorate, and a crystallized gold(i bromide product was formed. conside

r the other product and its phase, and then write the balanced molecular equation for this precipitation reaction.
Chemistry
2 answers:
mr_godi [17]3 years ago
4 0
Calcium bromide is CaBr2 
<span>Gold(I) perchlorate is AuClO4 </span>
<span>Crystallized gold(I) bromide would be AuBr(s). beginning with those, your equation would be: </span>
<span>CaBr2(aq) + AuClO4(aq) --> AuBr(s) </span>
<span>Now, the other product would be calcium perchlorate that would remain soluble. Since perchlorate has a -1 charge, you will need 2 of that ion to balance a calcium ion. Also, since you have 2 Br- ions on the left, you will need 2 AuBr(s) on the right. All of that leads to: </span>

<span>CaBr2(aq) + 2 AuClO4(aq) --> 2 AuBr(s) + Ca(ClO4)2(aq)</span>
beks73 [17]3 years ago
3 0

Answer:

CaBr2(aq) + 2 AuClO4(aq) --> 2 AuBr(s) + Ca(ClO4)2(aq)

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