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likoan [24]
3 years ago
13

Aqueous calcium bromide was mixed with aqueous gold(i perchlorate, and a crystallized gold(i bromide product was formed. conside

r the other product and its phase, and then write the balanced molecular equation for this precipitation reaction.
Chemistry
2 answers:
mr_godi [17]3 years ago
4 0
Calcium bromide is CaBr2 
<span>Gold(I) perchlorate is AuClO4 </span>
<span>Crystallized gold(I) bromide would be AuBr(s). beginning with those, your equation would be: </span>
<span>CaBr2(aq) + AuClO4(aq) --> AuBr(s) </span>
<span>Now, the other product would be calcium perchlorate that would remain soluble. Since perchlorate has a -1 charge, you will need 2 of that ion to balance a calcium ion. Also, since you have 2 Br- ions on the left, you will need 2 AuBr(s) on the right. All of that leads to: </span>

<span>CaBr2(aq) + 2 AuClO4(aq) --> 2 AuBr(s) + Ca(ClO4)2(aq)</span>
beks73 [17]3 years ago
3 0

Answer:

CaBr2(aq) + 2 AuClO4(aq) --> 2 AuBr(s) + Ca(ClO4)2(aq)

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A 27.3 g marble sliding to the right at 21.0 cm/s overtakes and collides with a 11.7 g marble moving in the same direction at 12
NISA [10]

Answer:

The answer to this is

The velocity of the 27.3Kg marble after collision is = 16.24 cm/s

Explanation:

To solve the question, let us list out the given variables and their values

Mass of first marble m1 = 27.3g

Velocity of the first marble v1 = 21.0 cm/s

Mass of second marble m2 = 11.7g

Velocity of the second marble v2 = 12.6 cm/s

After collision va1 = unknown and va2 = 23.7 cm/s

From Newton's second law of motion, force = rate of change of momentum produced

Hence m1v1 + m2v2 = m1va1 + m2va2 or

va1 = (m1v1 + m2v2 - m2va2)÷m2 or (720. 72-277.29)÷m1 → va1 = 16.24 cm/s

The velocity of the 27.3Kg marble after collision is = 16.24 cm/s

4 0
3 years ago
Calculate the molaity of a solution that is prepared by dissolving 50.4g sucrose (C12H22O11) in 0.332kg of water
maks197457 [2]

Answer:

0.443 mol/kg.

Explanation:

The formula for molal concentration (<em>b</em>) is

b = \frac{\text{moles of solute}}{\text{kilograms of solvent}}

\text{Moles of solute} = \text{50.4 g sucrose} \times \frac{ \text{1 mol sucrose}}{\text{342.30 g sucrose} } = \text{0.1472 mol sucrose}

b = \frac{ \text{0.1472 mol}}{ \text{0.332 kg}} = \text{0.443 mol}\cdot\text{kg}^{-1}

4 0
3 years ago
What do the formulas for table salt, NaCl, and water, H2O indicate about the compounds?
neonofarm [45]
The formulas indicate the number of elements in each compound. Notice the difference in ratios: 
NaCl is 1:1, while H2O is 2:1.
4 0
4 years ago
How many moles of nitrogen gas (N) are needed to react with 7.5 moles of hydrogen (H)?
Monica [59]

Answer:

2 moles N2⋅3 moles H21 Mole N2=6 moles H2

Explanation:

7 0
3 years ago
A compound is made by carbon, hydrogena and nitrogen and 1 g of this compound contains 91.5 mg of hydrogen and 424 mg of nitroge
ss7ja [257]

Answer:

C₄H₃N

Explanation:

To solve this question we must find the moles of each atom in order to find the empirical formula (Simplest ratio of atoms present in a molecule). With empirical formula and the molar mass of the compound we can find the molecular formula as follows:

<em>Moles H:</em>

91.5mg H * (1mmol / 1mg) =

91.5mmol H

<em>Moles N:</em>

424mg N * (1mmol / 14mg) =

30.286mmol N

The ratio of moles regard to moles N (The lower number of moles is:

H = 91.5mmolH / 30.286mmolN = 3.0

N = 30.286mmolN / 30.286mmolN = 1

empirical formula = CₓH₃N

The molar mass of this formula is:

12*x + 1*3 + 1*14 = 17g/mol

Solving for X:

12X + 17g/mol = 65g/mol

12X = 48g/mol

X = 4

There are 4 atoms of carbon and molecular formula is:

<h3>C₄H₃N</h3>
7 0
3 years ago
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