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likoan [24]
3 years ago
13

Aqueous calcium bromide was mixed with aqueous gold(i perchlorate, and a crystallized gold(i bromide product was formed. conside

r the other product and its phase, and then write the balanced molecular equation for this precipitation reaction.
Chemistry
2 answers:
mr_godi [17]3 years ago
4 0
Calcium bromide is CaBr2 
<span>Gold(I) perchlorate is AuClO4 </span>
<span>Crystallized gold(I) bromide would be AuBr(s). beginning with those, your equation would be: </span>
<span>CaBr2(aq) + AuClO4(aq) --> AuBr(s) </span>
<span>Now, the other product would be calcium perchlorate that would remain soluble. Since perchlorate has a -1 charge, you will need 2 of that ion to balance a calcium ion. Also, since you have 2 Br- ions on the left, you will need 2 AuBr(s) on the right. All of that leads to: </span>

<span>CaBr2(aq) + 2 AuClO4(aq) --> 2 AuBr(s) + Ca(ClO4)2(aq)</span>
beks73 [17]3 years ago
3 0

Answer:

CaBr2(aq) + 2 AuClO4(aq) --> 2 AuBr(s) + Ca(ClO4)2(aq)

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2 years ago
A group of students conducted an experiment to determine the effect of heat on the germination(sprouting) of sunflower seeds. Wh
pentagon [3]

what grade is this because apparently i like to know what grade it is before i solve it

3 0
3 years ago
Which organelle packages materials and distributes them throughout the cell?
Anastasy [175]
The golgi body i think
4 0
3 years ago
Read 2 more answers
1 C8H10(l) +21/2O2(g) → 8CO2(g) + 5H2O(g), Hcomb= ? Hf for C8H10(l) = +49.0kJ/mol C8H10(l) Use the balanced combustion reaction
nikklg [1K]

Answer:

H_{comb}=-4406kJ/mol

Explanation:

Hello,

In this case, the enthalpy of combustion is understood as the energy released when one mole of fuel, in this case octene, is burned in the presence of oxygen and is computed with the enthalpies of formation of the fuel, carbon dioxide and water as shown below (oxygen is circumvented as it is a pure element):

H_{comb}=8*\Delta _fH_{CO_2}+5\Delta _fH_{H_2O}-\Delta _fH_{C_8H_{10}}

Thus, since we already know the enthalpy of combustion of the fuel, for carbon and water we have -393.5 and -241.8 kJ/mol respectively, thereby, the enthalpy of combustion turns out:

H_{comb}=8*(-393.5kJ/mol)+5(-241.8kJ/mol)-49.0kJ/mol\\\\H_{comb}=-4406kJ/mol

Best regards.

4 0
4 years ago
g Write a molecular equation for the precipitation reaction that occurs (if any) when the following solutions are mixed. If no r
Mrac [35]

Answer:

CuBr₂(aq) + Pb(CH₃COO)₂(aq) → Cu(CH₃COO)₂(aq) + PbBr₂ (s)↓

Explanation:

We identify the reactants:

CuBr₂ and Pb(CH₃COO)₂

The products will be: Cu(CH₃COO)₂ and PbBr₂

You may know these information:

Salts from acetate are soluble.

Bromide can make solid salts with these cations: Ag⁺, Pb²⁺, Hg₂²⁺, Cu⁺

PbBr₂ is formed, so this will be our precipitate

The equation is:

CuBr₂(aq) + Pb(CH₃COO)₂(aq) → Cu(CH₃COO)₂(aq) + PbBr₂ (s)↓

8 0
3 years ago
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