For an equation y = a tan[b(x+c)], the period is equal to 2*pi/b, while the phase shift is c.
This equation can be rewritten as:
f(x) = 3 tan [4(x + pi/4)]
In this case, b = 4, c = pi/4
Then the period = 2*pi/b = pi/2.
The phase shift = pi/4 (to the left).
Label the 3 distinct sides of the box. I arbitrarily chose the letters a, b and c.
Use the info about areas as follows:
ab=54 in^2
ac=90 in^2
bc=60 in^2
Here you have 3 equations in 3 unknowns (a, b and c), which is enough info to use to determine a, b and c. Then the volume of the box is a*b*c.
Example: bc = 90, but c = 60/b. You could subst. 60/b for c in the 2nd and 3rd equation, which will eliminate c completely and leave you with 2 equations in 2 unknowns.
Continuing this procedure, I determined that a=9, b=6 and c=10. Thus, the volume of the box is V = 9*6*10 = 540 cubic inches (answer)
Answer:
The answer is D
Step-by-step explanation:
Answer:
c or d
Step-by-step explanation:
The domain is all real numbers.
(d)The range is y > 0.
Answer:
3 1/3
Step-by-step explanation:
2 + (-2/3)² ÷ 1/3
2 + 4/9 ÷ 1/3
2 + 4/9 × 3/1
2 + 12/9 = 2 + 4/3 = 2 + 1 1/3
= 3 1/3