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zimovet [89]
3 years ago
5

7 watermelons cost $8.96.Which equation would help determine the cost of the 5 watermelons?

Mathematics
2 answers:
HACTEHA [7]3 years ago
8 0

Answer:

x/5= $8.96/7

Step-by-step explanation:

postnew [5]3 years ago
4 0

Answer: ($8.96 / 7) * 5                        or $6.40

Step-by-step explanation: You need to find the price for one watermelon then multiply it by 5 to find the price of 5.

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The perimeter of the rectangle is 20\text{ cm}20 cm20, start text, space, c, m, end text. One side is 6\,\text{cm}6cm6, start te
Tamiku [17]

Answer: The lenght of the missing side is 4 cm

Step-by-step explanation:

The correct question is:

<em>The perimeter of the rectangle is 20cm . One side is 6cm. What is the length of the missing side?</em>

So, to answer it we have to apply the next formula:

Perimeter of a rectangle = 2 width + 2 length

Replacing with the values given: (assuming that the side given is the length of the rectangle)

20 = 2(6) + 2x

Solving for x:

20 =12 +2x

20-12 =2x

8 =2x

8/2 =x

4=x

The length of the missing side is 4 cm

Feel free to ask for more if needed or if you did not understand something.  

3 0
3 years ago
Read 2 more answers
Can someone please help meee with this ?
jok3333 [9.3K]

Answer:

the answer is A because

Step-by-step explanation:

1.A

5 0
3 years ago
A shopper paid $2.52 for 4.5 pounds of potatoes $7.75 for 2.5 pounds of broccoli and $2.45 for 2.5 pounds of pears. What is the
joja [24]

Potatoes: $2.52 / 4.5lbs = $0.56 / lb.

Broccoli: $7.75 / 2.5lbs = $3.1 / lb

Pears: $2.45 / 2.5lbs = $0.98 / lb

4 0
2 years ago
Which of the following is the correct expansion of the binomial (x + y)6?
Katen [24]
It would be 6x + 6y as the final expansion
7 0
2 years ago
Read 2 more answers
April shoots an arrow upward into the air at a speed of 32 feet per second from a platform that is 11 feet high. The height of t
dusya [7]

Answer:

27 ft

the maximum height of the​ arrow is 27 ft

Step-by-step explanation:

Given;

The height of the arrow is given by the function;

h(t) = -16t^2 + 32t + 11

Maximum height is at point when dh(t)/dt = 0.

Differentiating h(t), we have;

dh/dt = -32t + 32 = 0

Solving for t;

-32t = -32

t = -32/-32 = 1

t = 1 (time at maximum height is t = 1)

Substituting t=1 into h(t), to determine the value of maximum height;

h(max)= -16(1^2) + 32(1) + 11

h(max) = 27 ft

the maximum height of the​ arrow is 27 ft.

8 0
2 years ago
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