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jolli1 [7]
2 years ago
12

cos2x=____. Check all that apply. A. 1-2sin^2 x. B. 2sin^2 x-1. C. sin^2 x-cos^2 x. D. cos^2 x-sin^2 x

Mathematics
2 answers:
g100num [7]2 years ago
7 0
         cos 2 x = cos² x - sin² x = 1 - sin² x - sin² x = 1 - 2 sin² x.
         Answer: A ) 1 - sin² x and D ) cos² x - sin² x 
       
 Thank you.
Gnom [1K]2 years ago
3 0

Answer:

A & D

1-2sin^2x

cos^2x-sin^2x

Step-by-step explanation:

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nasty-shy [4]
The product of any number and 0 is zero. The expression is 1*0-0/y. 1*0 is obviously 0. 0/y is the same thing as 0 * 1/y, which is also zero. 0-0 is 0, so the answer is 0.
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Solve for a. Correct answer gets BRAINLIEST
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Hey there!!

Equation given :

A = h ( a + b ) / 2

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Divide by h on both sides

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Subtract by b on both sides

2A / h - ( b ) = a

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3 0
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Answer:

{ \tt{ \blue{  - {3x}^{2} + 4x + 4 }}}

Step-by-step explanation:

{ \tt{3x -  {2x}^{2}  + 4 -  {x}^{2} + x }} \\

» Collect second degree terms (x² coefficients) together and first degree terms (x coefficients) and constants

= { \tt{( - 2 - 1) {x}^{2} + (3 + 1)x + 4 }} \\  = { \boxed{ \tt{ \:  -  {3x}^{2}  + 4x + 4}}}

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Answer:

Angle C

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By applying sine rule in the given triangle,

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Therefore, Opposite angles of these sides will be in the same ratio.

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Largest angle of the triangle is angle C.

7 0
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