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notsponge [240]
3 years ago
13

What is the [OH-] of a solution whose pH=12.5

Chemistry
1 answer:
JulijaS [17]3 years ago
8 0

Answer:

0.316

Explanation:

ph --> H+ --> Oh-

H+ = 10^-ph

     = 10^-12.5

     = 3.16 x 10^-13

now for oh-

oh - =  1 x 10^-14 / 3.16 x 10^-13

       = .0316

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