Ask question

Ask question

All categories

3 years ago

8

1.25 moles of NOCl were placed in a 2.50 L reaction chamber at 427ºC. After equilibrium was reached, 1.10 moles of NOCl remained

. Calculate the equilibrium constant, K c, for the reaction 2NOCl(g) 2NO(g) + Cl 2(g).

1 answer:

kenny6666 [7]3 years ago

5 0

Answer:

5.6 × 10^4

this is ur answer hope it helps u

You might be interested in

Which subatomic particle is located outside the nucleus

Mrac [35]

Electrons is located outside the nucleus

5 0

2 years ago

What do many bases have in common?

Olin [163]

Answer:

D.) They often form hydroxide ions.

Explanation:

They generate hydroxide ions in water. they are soapy to touch and bitter in taste. they conduct electricity.

(all bases have hydroxide ions)

7 0

3 years ago

A. What is the pH of a solution with a [H+] of 6.8 x 10^-11?

inysia [295]

Answer:

[H+] = 6.8×10^-11

so, pH = - log[H+]

= - log [6.8×10^-11]

= -(-10.167)

= 10.167

6 0

2 years ago

Calculate the molarity of the solution.

Ainat [17]

Molarity = moles of solution/ liter of solution
4.32x10^2/20
432/20=
21.6 M

4 0

3 years ago

Read 2 more answers

A chemist mixes 75.0 g of an unknown substance at 96.5°C with 1,150 g of water at 25.0°C. If the final temperature of the system

AleksAgata [21]

To do this problem it is necessary to take into account that the heat given by the unknown substance is equal to the heat absorbed by the water, but considering the correct sign:

$-m\cdot c_e\cdot \Delta T = m_w\cdot c_e_w\cdot \Delta T_w$

Clearing the specific heat of the unknown substance:

$c_e = \frac{m_w\cdot c_e_w\cdot \Delta T_w}{m\cdot \Delta T} = -\frac{1\ 150\ g\cdot 4.184\frac{J}{g\cdot ^\circ C}\cdot (37.1 - 25.0)^\circ C}{75\ g\cdot (37.1 - 96.5)^\circ C}$

$c_e = -\frac{1\ 150\ g\cdot 4.184\frac{J}{g\cdot ^\circ C}\cdot 12.1^\circ C}{75\ g\cdot (-59.4)^\circ C} = \bf 13.07\frac{J}{g\cdot ^\circ C}$

6 0

2 years ago