Question

A 100100​-watt ​[W] motor ​(6060​% ​efficient) is available to raise a load 1010 meters​ [m] into the air. If the task takes 8080 seconds​ [s] to​ complete, how heavy was the load in units of kilograms​ [kg]?

Answer 1

Answer:

m = 48.93kg

The load is 48.93kg.

Explanation:

Given;

Power P = 100watts

Efficiency e = 60% = 0.60

distance d = 10 m

time taken t = 80 s

Acceleration due to gravity g = 9.81m/s

Workdone W can be expressed as;

W = ePt = Fd = mgd

ePt = mgd

Making m the subject of formula;

m = ePt/gd

Substituting the values;

m = (0.60×100×80)/(9.81×10)

m = 48.93kg

The load is 48.93kg.