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marta [7]
3 years ago
14

Explain the changes in molecular motion of particles as they change from solid to liquid to gas.

Physics
1 answer:
andrey2020 [161]3 years ago
8 0

Answer:

A rise in temperature increases the kinetic energy and speed of particles; it does not weaken the forces between them. The particles in solids vibrate about fixed positions; even at very low temperatures. Individual particles in liquids and gases have no fixed positions and move chaotically.

Explanation:

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What is an Ion and what does it do? (as much detail as you can put it into please)
user100 [1]

Answer:

Explanation:

Ions are substances the have lost or gained a certain amount of electrons. This makes them either positively or negatively charged.

They are charged particles.

  • Every atom is made up of protons, neutrons and electrons.
  • They are the three fundamental particles in any atom
  • The protons and neutrons are located in the central part called the nucleus of an atom. It is a simple tiny space.
  • Protons are positively charged particles. Neutrons do not carry any charges. Therefore, the nucleus is negatively charged.
  • Electrons are negatively charged particles. They occupy the bulk volume of an atom.

Every atom is neutral and the number of protons and electrons are the same. The equal number of protons and electrons balances to attain neutrality of an atom.

  Electrons are very easy to lose since they occupy the outermost shell.

  • When an atom loses an electron, the number of protons is more than electrons. Therefore, it becomes positively charged. Hence, its is called an anion.
  • An atom can also gain an electron, the electron number will be more than the protons. They then become negatively charged and are called cation.

Cations and ions are substances that are produced to attain a special type of bonding called electrovalent bonding.

Oppositely charged substances attracts one another.

5 0
3 years ago
10. A boy weighs 475 N. What is his mass? (acceleration due to gravity on Earth is 9.8m/s2 = g)
Darya [45]

Answer: mass = 48.47 kg.

Explanation:

Formula : Weight = mg  , where m = mass of body , g= acceleration due to gravity .

Given: Weight  = 475 N

g= 9.8\ m/s^2

Substitute all values in formula ,  we get

475= m \times9.8\\\\\Rightarrow\ m = \dfrac{475}{9.8}\\\\\Rightarrow\ m \approx 48.47\ kg

Hence, his mass = 48.47 kg.

7 0
3 years ago
8. Object A has a momentum of 80 Ns and collides and sticks to object B which has a momentum of -30 Ns. What is the momentum of
BigorU [14]

Given,

The momentum of the object A before the collision, p₁ =80 Ns

The momentum of the object B before the collision, p₂=-30 Ns

Given that the objects stick together after the collision.

From the law of conservation of momentum, the total momentum of a system should always remain the same. Thus the total momentum of the objects before the collision must be equal to the total momentum of the objects after the collision.

Thus,

p_1+p_2=p

Where p is the total momentum of the system at any instant of time.

On substituting the known values,

\begin{gathered} p=80-30 \\ =50\text{ Ns} \end{gathered}

Therefore the total momentum of the system is 50 Ns

Thus the momentum of the object AB after the collision is 50 Ns

6 0
1 year ago
You have a remote-controlled car that has been programmed to have velocity v⃗ =(−3ti^+2t2j^)m/s, where t is in s. At t = 0 s, th
DiKsa [7]

Answer:

The y-component of the car's position vector is 670m/s.

The x-component of the acceleration vector is -3, and the y-component is 40.

Explanation:

The displacement vector of the car with velocity

\boldsymbol{v}= (-3t\boldsymbol{i}+2t^2\boldsymbol{j})m/s

is the integral of the velocity.

Integrating \boldsymbol{v} we get the displacement vector \boldsymbol{d}:

\boldsymbol{d}=(-\dfrac{3}{2}t^2\boldsymbol{i}+\dfrac{2}{3}t^3\boldsymbol{j}  )

Now if the initial position if the car is

\boldsymbol{r}= (3.0\boldsymbol{i}+2.0\boldsymbol{j})

then the displacement of the car at time t is

\boldsymbol{d(t)}= \boldsymbol{r+d}

\boxed{\boldsymbol{d(t)}=(-\dfrac{3}{2}t^2+3.0\boldsymbol{i}+\dfrac{2}{3}t^3+2.0\boldsymbol{j}  )}

Now at t=10s, we have

\boxed{\boldsymbol{d(t)}=(-147\boldsymbol{i}+670\boldsymbol{j}  )}m

The y-component of the car's position vector is 670m/s.

The acceleration vector is the derivative of the velocity vector:

\boldsymbol{a(t)}=\dfrac{d\boldsymbol{v(t)}}{dt} =(-3\boldsymbol{i}+4t\boldsymbol{j})

and at t=10s it is

\boldsymbol{a(t)}=(-3\boldsymbol{i}+40\boldsymbol{j})m/s^2

The x-component of the acceleration vector is -3, and the y-component is 40.

5 0
3 years ago
a car moving with 72 km/hr towards east and another car with 90km/hr towards west find relative of A w.r to B​
hodyreva [135]

Answer:

please tell me what does w.r mean ? then I will try to give answer

7 0
3 years ago
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