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kow [346]
3 years ago
9

A 56 kg astronaut stands on a bathroom scale inside a rotating circular space station. The radius of the space station is 250 m.

The bathroom scale reads 42 kg. At what speed does the space station floor rotate?
Physics
1 answer:
Zielflug [23.3K]3 years ago
6 0

Answer:

The speed of space station floor is 49.49 m/s.

Explanation:

Given that,

Mass of astronaut = 56 kg

Radius = 250 m

We need to calculate the speed of space station floor

Using centripetal force and newton's second law

F=mg

\dfrac{mv^2}{r}=mg

\dfrac{v^2}{r}=g

v=\sqrt{rg}

Where, v = speed of space station floor

r = radius

g = acceleration due to gravity

Put the value into the formula

v=\sqrt{250\times9.8}

v=49.49\ m/s

Hence, The speed of space station floor is 49.49 m/s.

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Which describes acceleration involving only a change in direction?
Viefleur [7K]
If we consider any system moving with u<span>niform circular motion we can notice that the MAGNITUDE of the accelaration remains constant. However,  there is a change in the direction of the acceleration at every instant of time .

 As the object moves through the circle the acceleration changes its direction always pointing to the center of the circle.</span>
6 0
3 years ago
A 1,508 kg car rolling on a horizontal surface has a speed of 20.8 km/hr when it strikes a horizontal coiled spring and is broug
natali 33 [55]

Answer:

Approximately 1.79 \times 10^{5}\; {\rm N \cdot m^{-1}}, assuming friction between the vehicle and the ground is negligible.

Explanation:

Let m denote the mass of the vehicle. Let v denote the initial velocity of the vehicle. Let k denote the spring constant (needs to be found.) Let x denote the maximum displacement of the spring.

Convert velocity of the vehicle to standard units (meters per second):

\begin{aligned}v &= 20.8\; {\rm km \cdot h^{-1}} \times \frac{1000\; {\rm m}}{1\; {\rm km}} \times \frac{1\; {\rm h}}{3600\; {\rm s}} \\ &\approx 1.908\; {\rm m \cdot s^{-1}}\end{aligned}.

Initial kinetic energy ({\rm KE}) of the vehicle:

\begin{aligned}\frac{1}{2}\, m \, v^{2}\end{aligned}.

When the vehicle is brought to a rest, the elastic potential energy (\text{EPE}) stored in the spring would be:

\displaystyle \frac{1}{2}\, k\, x^{2}.

By the conservation of energy, if the friction between the vehicle and the ground is negligible, the initial \text{KE} of the vehicle should be equal to the {\rm EPE} of the vehicle. In other words:

\begin{aligned}\frac{1}{2}\, m \, v^{2} &= \frac{1}{2}\, k\, x^{2}\end{aligned}.

Rearrange this equation to find an expression for k, the spring constant:

\begin{aligned}k &= \frac{m\, v }{x^{2}}\end{aligned}.

Substitute in the given values m = 1508\; {\rm kg}, v \approx 1.908\; {\rm m\cdot s^{-1}}, and x = 6.87\; {\rm m}:

\begin{aligned}k &= \frac{m\, v }{x^{2}} \\ &\approx \frac{1508\; {\rm kg} \times 1.908\; {\rm m\cdot s^{-1}}}{(6.87\; {\rm m})^{2}} \\ &\approx 1.79 \times 10^{5}\; {\rm kg \cdot m \cdot s^{-2} \cdot m^{-3}}\\ &\approx 1.79 \times 10^{5}\; {\rm N \cdot m^{-1}}\end{aligned}

8 0
1 year ago
Which of these is a good example of Newton's First Law of inertia
Eddi Din [679]

Answer: The correct option is A.

Explanation:

Inertia is a state of an object or body to maintain its state. It resists any change in its state.

Newton's first law of inertia: When an objects is in state of motion, it will remain its state of motion or if it is in state of rest then it will remain in rest unless it is acted upon by external motion.

In the given options, a ball sits motionless on the ground is good example of Newton's first law motion. No external force is acting in this case.

In options (B), (C) and (D) , the external force is acting.

Therefore, the correct option is A.

8 0
3 years ago
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Which term best describes a fad diet
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Answer:

a fad diet is basically a diet that was a trend or that was popular for a short amount of time and makes unreasonable claims for fast and very much wanted results

Explanation:

6 0
2 years ago
If a basketball travels a distance of 4 meters in 5 seconds, what is its average speed?
aliya0001 [1]

Average speed = (distance covered) / (time to cover the distance)


Average speed = (4 meters) / (5 seconds)


Average speed = (4/5) (meters/seconds)


Average speed = 0.8 m/s

5 0
3 years ago
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