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borishaifa [10]
2 years ago
9

4. A person who walks one block north, one block east, one block south,

Physics
1 answer:
pychu [463]2 years ago
3 0

Answer:

Displacement should be 0

Explanation:

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Answer:

A yardstick and a baseball bat

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A father is pulling his child on a sled in the snow. According to Newton’s Third Law, the force the father exerts on the sled is
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That is because there are other forces like the friction forces that apply differently on both of them. The frictional forces applied to the sled are smaller than they are on the father, for example, so it's possible for him to pull it.
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Dr. Man was studying a fossil from a dig in a desert when he noticed that the organism had evidence of fins.
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What organism? Picture?
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2 years ago
A ski hill is angled 20° above the horizontal. If a skier starts from rest at the top of the hill, how fast will she be travelin
MaRussiya [10]

Answer:

20 m/s

Explanation:

First, we calculate for the acceleration down the incline using a = gsin\theta.

a = (9.80)sin(20°)

a = 3.35

Then, we use one of the kinematics equations, {v_{f}}^{2} = {v_{i}}^{2} + 2 a\Delta s.

v_{i} = 0 m/s

a = 3.35

\Delta s = 62 m

v_{f} = \sqrt{2(3.35)(62)}

v_{f} =20.381 = 20 m/s

6 0
2 years ago
An ideal gas is brought through an isothermal compression process. The 3.00 mol 3.00 mol of gas goes from an initial volume of 2
ozzi

Answer:

The answers can be found by considering the isothermal expansion equation as well as the ideal gas equation from where we have

The temperature T = 602.64K and the final pressure P = 110.24MPa

Explanation:

Numbeer of moles of gas = 3.00 mol  

initial volume = 230.8×10−6 m3  

final volume = 133.4×10−6 m3 .

released energy =  8240 J

Temperature = Constant = T

Pressure =  p_{f} =unknown

From the relation the combined ideal gas law, PV = nRT

Where R = 8.314 4621.JK−1mol−1

we have The release energy from compression P1V1 -P2V2

-qrev = -nRTln(\frac{V_{2} }{V_{1} }) = 8240J

n = 3

Hence -nRTln(\frac{V_{2} }{V_{1} }) =  3×8.314 462×ln(\frac{133.4}{230.8}) × T=  -8240 J

or -13.67×T = -8240J, thus T = -8240/-13.67 = 602.64K

The Final pressure is given by

PV = n×R×T from where we have V = final volume thus

P = (n×R×T)/V = (3×8.134×602.64)÷(133.4×10^{-6}) = 110237041.1 N/m^{2} = 110.237MPa

8 0
3 years ago
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