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Slav-nsk [51]
3 years ago
6

Simplify (1-cos theta)(1+cos theta) over (1-sin theta) (1+ sin theta)

Mathematics
1 answer:
slega [8]3 years ago
4 0
\bf sin^2(\theta)+cos^2(\theta)=1\to 
\begin{cases}
cos^2(\theta)=1-sin^2(\theta)\\
sin^2(\theta)=1-cos^2(\theta)
\end{cases} \\\\
-------------------------------\\\\
\stackrel{\textit{difference of squares}}{\cfrac{[1-cos(\theta )][1+cos(\theta )]}{[1-sin(\theta )][1+sin(\theta )]}}\implies \cfrac{1^2-cos^2(\theta )}{1^2-sin^2(\theta )}\implies \cfrac{1-cos^2(\theta )}{1-sin^2(\theta )}
\\\\\\
\cfrac{sin^2(\theta )}{cos^2(\theta )}\implies tan^2(\theta )
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Plugging in the relevant values;

12.5 = 25 × e^(-0.1229t)

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3 years ago
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kozerog [31]

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Question (2)

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3 years ago
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