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4 years ago

Covalent bonds form between hydrogen and oxygen atoms in a water molecule as a result of:

1 answer:

5 0

Covalent bonds form between hydrogen and oxygen atoms in a water molecule as a result of - Sharing of electrons between atoms.

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A flask of fixed volume contains 1.00 mole of gaseous carbon dioxide and 88.0 g of solid carbon dioxide. the original pressure a

Lynna [10]

Are u sure this will work

5 0

4 years ago

Read 2 more answers

In carbon dioxide (CO2), how many grams of oxygen (O) would there be if there are 24 grams of carbon (C)?

Zarrin [17]

Answer:

64g of Oxygen

Explanation:

Firstly, carbon and oxygen react to form CO2 as follows;

C + O2 => CO2

According to the equation, one mole of C reacts with one mole of O2 to give one mole of CO2

Since molar mass of C= 12g/mol, O= 16g/mol

One mole of (C) contains 12g

One mole of O2 contains 16(2) = 32g

Hence, If there are 24g of C, there would be 24 × 32 / 12

= 768/12

= 64g

Hence, there would be 64g of oxygen if there are 24g of Carbon

6 0

4 years ago

A hypothetical element has an atomic weight of 48.68 amu. It consists of three isotopes having masses of 47.00 amu, 48.00 amu, a

Morgarella [4.7K]

Answer : The percent abundance of the heaviest isotope is, 78 %

Explanation :

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$

As we are given that,

Average atomic mass = 48.68 amu

Mass of heaviest-weight isotope = 49.00 amu

Let the percentage abundance of heaviest-weight isotope = x %

Fractional abundance of heaviest-weight isotope = $\frac{x}{100}$

Mass of lightest-weight isotope = 47.00 amu

Percentage abundance of lightest-weight isotope = 10 %

Fractional abundance of lightest-weight isotope = $\frac{10}{100}$

Mass of middle-weight isotope = 48.00 amu

Percentage abundance of middle-weight isotope = [100 - (x + 10)] % = (90 - x) %

Fractional abundance of middle-weight isotope = $\frac{(90-x)}{100}$

Now put all the given values in above formula, we get:

$48.68=[(47.0\times \frac{10}{100})+(48.0\times \frac{(90-x)}{100})+(49.0\times \frac{x}{100})]$

$x=78\%$

Therefore, the percent abundance of the heaviest isotope is, 78 %

5 0

3 years ago

Read 2 more answers

Which element has 16 protons in its nucleus? neon oxygen sodium sulfur

Assoli18 [71]

Answer: Sulfur

Explanation: Sulfur has 16 protons, silicon has 14 protons, and gold has 79 protons.

6 0

3 years ago

How many oxygen atoms are present in 0.500 mol carbon dioxide

Paha777 [63]

Carbon dioxide = CO2

.5 mol CO2 = 1 mol O

1 mol O = 6.022140857 × 10^23 Oxygen atoms

6 0

3 years ago