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2 years ago

PLEASE HLEP I WILL GIVE BRAINLIEST

Chemistry

2 answers:

Leno4ka [110]2 years ago

8 0

D will be the answer !!!!!!:))

denis23 [38]2 years ago

5 0

D is the correct answer

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The Ksp of yttrium iodate, Y(IO3)3 , is 1.12×10−10 . Calculate the molar solubility, s , of this compound.

torisob [31]

Answer:

1.427x10^-3mol per L

Explanation:

$Y(IO_{3} )_{3} ---- Y^{3+} +IO_{3} ^{3-}$

I could use ⇌ in the math editor so I used ----

from the question each mole of Y(IO3)3 is dissolved and this is giving us a mole of Y3+ and a mole of IO3^3-

Ksp = [Y^3+][IO3-]^3

So that,

1.12x10^-10 = [S][3S]^3

such that

1.12x10^-10 = 27S^4

the value of s is 0.001427mol per L

= 1.427x10^-3mol per L

so in conclusion

the molar solubility is therefore 1.427x10^-3mol per L

3 0

2 years ago

GET IT RIGHT FOR BONUS

storchak [24]

Answer:

Sand

Explanation:

with salt distillation will work, heat the solution and collect the water in a seperate beaker

With sugar you do the same, boil away the water and collect the water vapour, you'll be left with sugar in the original container and water if you collected it

Use a fraction of column and heat the solution, the alcohol will be seperated out

Sand is the only one that uses mechanical filtration

5 0

2 years ago

Choose three physical properties that can be used to identify pure substances. (select all that apply.) melting point degree of

ch4aika [34]

Malleable ductile and sonorous

5 0

2 years ago

In general, the rate of evaporation increases with ___________.

mars1129 [50]

Answer:

heat increase, pressue loss, altitude gain,

Explanation:

6 0

2 years ago

The addition of hydrochloric acid to a silver nitrate solution precipitates silver chloride according to the reaction:

Nimfa-mama [501]

Answer:

Enthalpy change for the reaction is -67716 J/mol.

Explanation:

Number of moles of $AgNO_{3}$ in 50.0 mL of 0.100 M of $AgNO_{3}$

= Number of moles of HCl in 50.0 mL of 0.100 M of HCl

= $\frac{0.100}{1000}\times 50.0$ moles

= 0.00500 moles

According to balanced equation, 1 mol of $AgNO_{3}$ reacts with 1 mol of HCl to form 1 mol of AgCl.

So, 0.00500 moles of $AgNO_{3}$ react with 0.00500 moles of HCl to form 0.00500 moles of AgCl

Total volume of solution = (50.0+50.0) mL = 100.0 mL

So, mass of solution = ( $100.0\times 1.00$ ) g = 100 g

Enthalpy change for the reaction = -(heat released during reaction)/(number of moles of AgCl formed)

= $\frac{-m_{solution}\times C_{solution}\times \Delta T_{solution}}{0.00500mol}$

= $\frac{-100g\times 4.18\frac{J}{g.^{0}\textrm{C}}\times [24.21-23.40]^{0}\textrm{C}}{0.00500mol}$

= -67716 J/mol

[m = mass, c = specific heat capacity, $\Delta T$ = change in temperature and negative sign is included as it is an exothermic reaction]

4 0

2 years ago