F(4-1) = 13+4(4)
f(3) = 13+4(4)
f(3) = 13+16
f(3) = 29
Hope this helps!! ^^
The transformation that maps quadrilateral 1 onto quadrilateral 2 is a translation followed by a dilation with a scale factor of 1/2
From the question, we have the following highlights
- The quadrilaterals are similar (not congruent)
- Quadrilateral 2 is twice the size of quadrilateral 1
The above highlight (1) means that, quadrilateral 1 can be translated to get 2.
After the translation, the new quadrilateral 1 can then be dilated by 1/2 (this is so because quadrilateral 2 is twice the size of quadrilateral 1.
Hence, the true statement is: the transformation that maps quadrilateral 1 onto quadrilateral 2 is a translation followed by a dilation with a scale factor of 1/2
Read more about transformation at:
brainly.com/question/4057530
Answer:
0.9728
Explanation:
P(launch), p = 80% = 0.8
(1 - p) = 1 - 0.80 = 0.2
Number of launches = 4
We can apply the binomial probability formula :
P(x =x) = nCx * p^x * (1 - p)^(n - r)
Probability that More than 1 is launched
P(x > 1) = p(x = 2) + p(x = 3) + p(x = 4)
P(x = 2) :
4C2 * 0.8^2 * 0.2^2
6 * 0.64 * 0.04 = 0.1536
P(x = 3) :
4C3 * 0.8^3 * 0.2^1
4 * 0.512 * 0.2 = 0.4096
P(x = 4) :
4C4 * 0.8^4 * 0.2^0
1 * 0.4096 * 1 = 0.4096
P(x > 1) = 0.1536 + 0.4096 + 0.4096
P(x > 1) = 0.9728
