8*a=32
32:8=a
4=a
4+26=b
30=b
The system of equations has infinitely many solutions
<em><u>Solution:</u></em>
<em><u>Given system of equations are:</u></em>
-3x + 3y = 12 ------- eqn 1
y = x + 4 --------- eqn 2
We have to find the solution to the system of equations
We can use substitution method
Substitute eqn 2 in eqn 1
-3x + 3(x + 4) = 12
-3x + 3x + 12 = 12
-3x + 12 = -3x + 12
If we have terms with same terms on both sides of equal sign, then we have infinitely many solutions
Thus the system of equations has infinitely many solutions
It's A.....................................................
In order to solve using elimination, we need to be able to get rid of one variable, so that we can solve for the other. We need to subtract these two equations given from one another, or multiply the bottom equation by a negative and add them together.
(-5x + 6y = 8) - (-5x + 4y = 2)
(-5x + 6y = 8) + (5x - 4y = -2)
0x + 2y = 6
2y = 6
y = 3
Now that we know the value of one variable, we can take that value and plug it back into one of the original equations and solve for the value of the other variable.
-5x + 6y = 8
-5x + 6(3) = 8
-5x + 18 = 8
-5x = -10
x = 2
The solution to this system of equations is (2, 3).
Hope this helps!! :)
