Question

A bag comtains 2 red marbles, 3 blue marbles, and 4 green marbles. What is the probability of choosing a blue marble, and without replacing it, drawing a green marble, and without replacing it, drawing another green marble.
A) 1/12
B) 5/12
C) 1/14
D) None of the above​

Answer 1

Answer:

1 /14

Step-by-step explanation:

P(B, G, G) = $\frac{3}{9}$ · $\frac{4}{8}$ · $\frac{3}{7}$

                = $\frac{1}{3}$ · $\frac{1}{2}$ · $\frac{3}{7}$

                 =  $\frac{1}{14}$