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goblinko [34]
3 years ago
13

Balance the redox reaction equation (occurring in acidic solution) and choose the correct coefficients for each reactant and pro

duct. __MnO4−(aq)+Ag(s)+H+(aq)→Mn2+(aq)+Ag+(aq)+__H2O(l)
Chemistry
1 answer:
dlinn [17]3 years ago
5 0

Explanation:

A balanced redox chemical equation is an equation that contains same number of atoms on both reactant and product side. Also, it contains same total charge on reactant and product side.

For example, MnO^{-}_{4}(aq) + Ag(s) + H^{+}(aq) \rightarrow Mn^{2+}(aq) + Ag^{+}(aq) + H_{2}O(l)

Number of atoms on reactant side are as follows.

Mn = 1

O = 4

Ag = 1

H = 1

Number of atoms on product side are as follows.

Mn = 1

O = 1

Ag = 1

H = 2

Therefore, to balance the equation multiply H^{+}(aq) on reactant side by 8 and multiply H_{2}O on product side by 4.

      MnO^{-}_{4}(aq) + Ag(s) + 8H^{+}(aq) \rightarrow Mn^{2+}(aq) + Ag^{+}(aq) + 4H_{2}O(l)

Now, total charge on reactant side is +7 but total charge on product side is +2. Therefore, to balance the charges we multiply Ag(s) on reactant side by 5 and Ag^{+} on product side by 5.

Therefore, completely balanced redox reaction equation will be as follows.

           MnO^{-}_{4}(aq) + 5Ag(s) + 8H^{+}(aq) \rightarrow Mn^{2+}(aq) + 5Ag^{+}(aq) + 4H_{2}O(l)

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They also weigh the cost aspect along with the benefit of the ongoing environmental issue. They try to come up with something which appears to be cost effective and result bearing.

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3 years ago
How can we find the volume of this fish tank? Please I needed but Good
r-ruslan [8.4K]
<h3><u>Answer;</u></h3>

Find the number of 1-foot cubes that fill the fish tank

<h3><u>Explanation;</u></h3>

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A 15.0 g piece of graphite is heated to 100.0°C and placed in a calorimeter. The
LenKa [72]

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Explanation:

4 0
3 years ago
Read 2 more answers
Calcium nitrate and ammonium fluoride react to form calcium fluoride, dinitrogen monoxide, and water vapor. How many grams of di
pychu [463]

Answer:

16.79 grams of dinitrogen monoxide are present after 31.3 g of calcium nitrate and 38.7 g of ammonium fluoride react completely. And calcium nitrate is a limiting reactant. Explanation:

Ca(NO_3)_2(aq)+2NH_4F(aq)\rightarrow CaF_2(aq)+2N_2O(g)+4H_2O(g)

Moles of calcium nitrate = \frac{31.3 g}{164 g/mol}=0.1908 mol

Moles of ammonium fluoride = \frac{38.7 g}{37 g/mol}=1.046 mol

According to reaction , 2 moles of ammonium fluoride reacts with 1 mole of calcium nitrate.

Then 1.046 moles of ammonium fluoride will react with :

\frac{1}{2}\times 1.046 mol=0.523 mol calcium nitarte .

This means that ammonium fluoride is in excess amount and calcium nitrate is in limiting amount.

Hence, calcium nitrate is a limiting reactant.

So, amount of dinitrogen monoxide will depend upon moles of calcium nitrate.

So, according to reaction , 1 mole of calcium nitarte gives 2 moles of dinitrogen monoxide gas .

Then 0.1908 moles of calcium nitrate will give:

\frac{2}{1}\times 0.1908 mol=0.3816 molof dinitrogen monoxide gas.

Mass of 0.03816 moles of dinitrogen monoxide gas:

0.03816 mol × 44 g/mol = 16.79 g

16.79 grams of dinitrogen monoxide are present after 31.3 g of calcium nitrate and 38.7 g of ammonium fluoride react completely. And calcium nitrate is a limiting reactant.

8 0
3 years ago
Help me get this right no links
Ivenika [448]

Answer:

What's the question? or show a picture

7 0
3 years ago
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