Using the formula velocity = distance/time, how fast does sound travel in air at 20 degrees C given a distance of 500 m and 3.92
1 answer:
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P₄0₆ + 20₂
⇒ P₄0₁₀
Explanation:
The overall equation for the reaction that produces P₄0₁₀ is :
P₄0₆ + 20₂
⇒ P₄0₁₀
Now let us derive this equation:
Given equations:
P₄ + 30₂
⇒ P₄0₆
equation 1;
P₄ + 50₂
⇒ P₄0₁₀
equation 2;
To get the overall combined equation, the equation 1 must be reversed and added to equation 2:
P₄0₆ ⇒ P₄
+ 30₂
equation 3
+
equation 2:
P₄ + 50₂
+ P₄0₆
⇒ P₄0₁₀
+ P₄
+ 30₂
cancelling specie that appears on both sides and removing excess oxygen gas on the reactant side gives;
P₄0₆ + 20₂
⇒ P₄0₁₀
learn more:
Net equation brainly.com/question/2947744
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