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AleksAgata [21]
3 years ago
14

Kenny likes to count his money by tiling it on his table as shown. The diameter of a quarter is 24.26 mm. Find the area of the t

able not covered in quarters. Round your answer to the nearest hundredth.
Mathematics
1 answer:
ElenaW [278]3 years ago
5 0
First we have to assume that each quarter touched each other. Hence the area of the table not covered by the coins (A) is equal to the total area of the table (At) minus the total area of the coins (Ac). Coins are circle, so A =  \pi  r^{2} and r =24.26mm. The area of one coin is then 1848.98mm^2. Hence the equation is A = At - xAc where x is the number of coins. 
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Pls I need help with this ASAP
andrew-mc [135]

Answer:

The answer is 30.

Step-by-step explanation:

All of those angles will add up to 360 degrees. Since 150 is the same as the angle across from it that means the other one is 150. Add those 2 together that gets 300. So what is left? It is 60. So divide 60 between those two angles and you get 30.

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3 years ago
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Due tomarrow help me in this i need help in a and c
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Answer:

A.)4x+8

C.)8x+12

Step-by-step explanation:

Same steps you did

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3 years ago
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Perform the following operations and write the answers in radical form. Part A:√7+√3+√98−√18 Part B:3√5−3√11+2√121−3√90
Sveta_85 [38]

Answer:

  1. \sqrt{7}+\sqrt{3}+4\sqrt{2}
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Step-by-step explanation:

Part A ;

\sqrt{7} +\sqrt{3} +\sqrt{98} -\sqrt{18} \\\\\sqrt{98}=7\sqrt{2}\\\sqrt{18}=3\sqrt{2}\\\\=\sqrt{7}+\sqrt{3}+7\sqrt{2}-3\sqrt{2}\\\\\mathrm{Add\:similar\:elements:}\:7\sqrt{2}-3\sqrt{2}=4\sqrt{2}\\\\=\sqrt{7}+\sqrt{3}+4\sqrt{2}

Part B ;

3\sqrt{5}  - 3\sqrt{11} + 2\sqrt{121} -3\sqrt{90} \\\\2\sqrt{121}=22\\3\sqrt{90}=9\sqrt{10}\\\\=3\sqrt{5}-3\sqrt{11}+22-9\sqrt{10}

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=y%20%3D%20x%20%7B%7D%5E%7B2%7D%20-%209x%20%2B%2014" id="TexFormula1" title="y = x {}^{2} - 9x
svetoff [14.1K]

Answer:

a = - \frac{9}{2} , b = - \frac{25}{4}

Step-by-step explanation:

To obtain the required form use the method of completing the square

add/ subtract ( half the coefficient of the x- term)² to x² - 9x

y = x² + 2(- \frac{9}{2} )x + \frac{81}{4} - \frac{81}{4} + 14

  = (x - \frac{9}{2} )² - \frac{81}{4} + \frac{56}{4}

  = (x - \frac{9}{2} )²- \frac{25}{4} ← in the form (x + a)² + b

with a = - \frac{9}{2} and b = - \frac{25}{4}

8 0
3 years ago
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lys-0071 [83]
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3 years ago
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