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3 years ago

What is the x value for the solution -x+2y=6 6y =x+18

Mathematics

1 answer:

Alika [10]3 years ago

5 0

For the given set of equations, x = 0 and y = 3.

Step-by-step explanation:

Step 1:

From the question,

$-x + 2y = 6$ , take this as equation 1,

$6y =x+18, x - 6y = -18$ , take this as equation 2.

Step 2:

When we add equation 1 and equation 2, the x variable is canceled out and y can be calculated.

$-4y = -12, y = \frac{-12}{-4}, y = 3.$

Step 3:

Substituting this value of y in any of the previous equations we will get x's value.

Here this value of y i.e y = 3 is substituted in equation 1.

$-x + 6 = 6, -x = 6 -6, -x=0, x=0.$

So we have x = 0 and y = 3.

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2 years ago

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3 years ago

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Answer:

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4 years ago

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$\bf \displaystyle \int\limits_{0}^{28}\ \cfrac{1}{\sqrt[3]{(8+2x)^2}}\cdot dx\impliedby \textit{now, let's do some substitution}\\\\
-------------------------------\\\\
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-------------------------------\\\\$

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\begin{array}{llll}
\textit{now let's change the bounds}\\
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\end{array}\\\\
-------------------------------\\\\
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\\\\\\
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$\bf \\\\
-------------------------------\\\\
\displaystyle \cfrac{1}{2}\int\limits_{8}^{64}\ u^{-\frac{2}{3}}\cdot du\implies \cfrac{1}{2}\cdot \cfrac{u^{\frac{1}{3}}}{\frac{1}{3}}\implies \left. \cfrac{3\sqrt[3]{u}}{2} \right]_8^{64}
\\\\\\
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