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Snezhnost [94]
3 years ago
7

Two long straight wires are parallel to each other and are separated by 78 mm. The current in wire 1 is 3.55 A and the current i

n wire 2 is 2.75 A. What is the force per unit length between the two wires?
Physics
1 answer:
lord [1]3 years ago
5 0

Answer:

2.5\cdot 10^{-5}N

Explanation:

The force per unit length between two current-carrying wires is given by:

\frac{F}{L}=\frac{\mu_0 I_1 I_2}{2\pi r}

where

\mu_0 is the vacuum permeability

I_1, I_2 are the two currents

r is the separation between the wires

In this problem, we have

I_1 =3.55 A is the current in the first wire

I_2 = 2.75 A is the current in the second wire

r=78 mm=0.078 m is the separation between the wires

Substituting into the equation, we find

\frac{F}{L}=\frac{(4\pi \cdot 10^{-7} H/m)(3.55 A)(2.75 A)}{2\pi (0.078 m)}=2.5\cdot 10^{-5}N

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