Answer:
s = 0.9689 m
Explanation:
given,
Height of fall of paratroopers = 362 m
speed of impact = 52 m/s
mass of paratrooper = 86 Kg
From from snow on him = 1.2 ✕ 10⁵ N
now using formula
F = m a
a = F/m


Using equation of motion
v² = u² + 2 a s


s = 0.9689 m
The minimum depth of snow that would have stooped him is s = 0.9689 m
First we write the kinematic equations
a
v = a * t + vo
r = (1/2) at ^ 2 + vo * t + ro
We have then that:
(10.4 - t) = time that they run at their maximum speed
For Laura:
d = (1/2) at ^ 2 + (at) (10.4 - t)
100 m = (1/2) a (1.96) ^ 2 + [(1.96) a] (8.44)
100 = 1.9208a + 16.5424a
100 = 18.4632a
a = 100 / 18.4632 = 5.42 m / s ^ 2
For Healen:
100 = (1/2) a (3.11) ^ 2 + [(3.11) a] (7.29)
100 = 4.83605a + 22.6719a
100 = 27.50795a
a = 100 / 27.50795
a = 3.64 m / s ^ 2
Answer:
the acceleration of each sprinter is
Laura: 5.42 m / s ^ 2
Healen 3.64 m / s ^ 2
Answer:
0.99kgm/s
Explanation:
Given parameters:
Initial momentum = 5.8kgm/s
Final momentum = 6.79kgm/s
Unknown:
Magnitude of the impulse applied to the baseball = ?
Solution:
To solve this problem;
The impulse applied to the baseball can be found by using the expression below:
Impulse = Final momentum - Initial momentum
Impulse = 6.79kgm/s - 5.8kgm/s = 0.99kgm/s
Force applied on the car due to engine is given as
towards right
Also there is a force on the car towards left due to air drag
towards left
now the net force on the car will be given as

now we can say that since the two forces are here opposite in direction so here the vector sum of two forces will be the algebraic difference of the two forces.
So we can say



So here net force on the car will be 150 N towards right and hence it will accelerate due to same force.