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sleet_krkn [62]
3 years ago
11

Calculate the frequency of the 3rd normal mode of a guitar string of length 40.0cm and mass 0.5g when stretched with a tension o

f 80N.
Physics
1 answer:
Alexandra [31]3 years ago
7 0

Answer:

Explanation:

For third normal mode of vibration

l = \frac{3\lambda}{2}  , λ is wavelength , l is length of string .

.4 = \frac{3\lambda}{2}

λ = .267 m

velocity = \sqrt{\frac{T}{m} }

T is tension and m is mass unit length

m = .5 x 10⁻³ / 40 x 10⁻²

= .00125 kg / m

Putting the values

velocity = \sqrt{\frac{80}{.00125} }

= 253 m /s

frequency

= velocity / λ

= 253 / .267

= 947.5 Hz .

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Un barco va a una velocidad de 45 ml/h, luego el capitán ordena acelerar hasta que la velocidad hasta que la velocidad sea de 60
Sophie [7]

Pregunta completa:

Un barco va a una velocidad de 45 ml/h, luego el capitán ordena acelerar hasta que la velocidad hasta que la velocidad sea de 60 mll/h. si la operación dura 30 minutos.

A cual fue la aceleracion?

B qué distancia recorre?

Responder:

30 millas / hora

26.25 mi

Explicación:

Dado que :

Velocidad inicial, u = 45 mi / hr

Velocidad final, v = 60 mi / hr

Tiempo, t = 30 minutos = 30/60 = 0,5 h

Aceleración, a = cambio de velocidad con el tiempo;

a = (v - u) / t

a = (60 - 45) / 0,5

a = 15 / 0,5

a = 30 millas / h²

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