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Illusion [34]
3 years ago
12

If the cube is divided into two equal parts by a plane parallel to the face defined by vertices 2, 3, 6, and 7, what will be the

area of the cross-section?
Mathematics
1 answer:
notsponge [240]3 years ago
5 0
The area of the cross-section is 169 sq. cm. 

That is the correct answer to this problem
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40% of the children in a sports club play badminton. 25% of the children who play badminton also play squash. There are 11 child
Keith_Richards [23]

Answer:

There are 110 children total in the sports club

Step-by-step explanation:

To get this answer, its actually easier than it seems. You might need a calculator however.

First you start with the 11 children who play both badminton and squash, then, you divide that by 0.25 (25%) to get 44.

Next you take 44 and divide it by 0.4 (40%) to get 110.

And there you go! If you want to make sure you got it right simply start with 110 and multiply it by 0.4 then multiply the number/decimal you get by 0.25. You should get 11 to confirm your answer :)

6 0
3 years ago
Look at picture because I cannot put square roots in
monitta

Answer:

45

Step-by-step explanation:

7 0
3 years ago
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JulijaS [17]
He measured the height of the box to be 7 in. Then<span>, </span>Stephan drew a line from the center of one of the hexagons to each of its vertices and noticed that<span> all .</span>
4 0
3 years ago
I NEED HELP PLEASEEE! <br> thank you :)
Artemon [7]

Answer:

70°

Step-by-step explanation:

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intercepted arc = 360° - 220° = 140°, thus

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4 years ago
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