Composing functions means that the input of the outer functions is the output of the inner function.
In fact, you can rewrite the circle notation as

So, we can substitute g(x) with its expression:

And since f(x)=x+5, we simply have to add 5 to its input:

Similarly, we have, substituting f with its expression,

And since g(x)=4x+2, we have to multiply the input by 4 and add 2:

I think it is
I4.23 x 10 ^4
These functions are expressed in the factored form: what this means is that say for the first one y=(x-4)(x-1)(2+x)(3+x) ... when x=4, the first bracket becomes 0. Same for x=1, x=-2, x=-3 ...
If you were to graph this, you would see that the function's line interesects the x-axis at these points... when x=4, when x=1, etc etc.
Thus, take a look at the zeroes of the graph. At which x points do they interscet the x-axis? You can determine the equation of your graph by this.