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shutvik [7]
2 years ago
6

Third derivative of xsinx?

Mathematics
1 answer:
Brut [27]2 years ago
6 0
Hello here is a solution :
f(x) = xsin(x)
f'(x) =( x)'sin(x) +x(sin(x))'
f'(x) = 1. sin(x)+x cos(x)
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What is the growth factor of the following example? Assume time is measured in the units given.
My name is Ann [436]

Answer:

B. 0.20 per century

Step-by-step explanation:

I calculated it logically

8 0
2 years ago
4x−3=16=4(x−3)=16 <br> Do they have the same solution?
AnnZ [28]

Answer:

no

Step-by-step explanation:

4x -3 = 16

x=19/4

4(x-3) = 16: Distribute the number in the parenthesis with 4 and you get:

4x-12=16

x=7

4x-12=16 is not the same as 4x-3=16

Therefore they do not have the same solution.

5 0
3 years ago
Read 2 more answers
1) The population of a town was7652in 2016. The population grows at a rate of 1.6%annually.(a)Use the exponential growth model t
marshall27 [118]

Answer:

1. a) population of the town in 2024 = 8697

2.) the earthquake with a magnitude of 8 is a <u>100 times stronger</u> than an earthquake with a magnitude of 6.

Step-by-step explanation:

1) the population of a town was, N_{0}   = 7652 in 2016.

a) Exponential growth model is given by N(t) = N_{0} e^{kt} where t is the time in years after 2016.

 Year 2016 is when t = 0.

  k = growth rate constant = 1.6% = 0.016

 i) therefore the population of the town in 2024

    = N = N_{0} e^{kt}  = 7652e^{0.016\times8}  = 8697   ( to the nearest whole number)

2.) log (I \times M \times S) = magnitude of earthquake  where I is the Intensity of the earthquake and S is the intensity of a standard earthquake

therefore  I \times M \times S = 10^{magnitude\hspace{0.1cm}of\hspace{0.1cm}earthquake}

therefore \frac{strength\hspace{0.1cm}of\hspace{0.1cm}earthquake\hspace{0.1cm}1 }{strength\hspace{0.1cm}of\hspace{0.1cm}earthquake\hspace{0.1cm}2}  = \frac{10^{8} }{10^{6} }  = 100

 

3 0
3 years ago
Factor the expression below.4x2 - 1
marusya05 [52]

Answer:

C. (2x – 1)(2x + 1)

Step-by-step explanation:

4x² – 1 = (2x)(2x) – 1 = (2x – 1)(2x + 1)

5 0
2 years ago
Read 2 more answers
A function is expressed by the equation y=0.3x−6. For what value of the independent variable will the value of the function be e
Anna11 [10]

Answer:

0; 10; 20

Step-by-step explanation:

x is the independent variable

y is the dependent variable

y is dependent on x

a) For what value of the independent variable will the value of the function be equal to −6

y=0.3x−6

-6 = 0.3x-6

0=0.3x

x = 0

Therefore, if the independent variable is 0, the value of the function will be -6.

b) For what value of the independent variable will the value of the function be equal to −3

y=0.3x−6

-3 = 0.3x-6

0.3x = -3+6

0.3x = 3

x = 3/0.3

x = 10

Therefore, if the independent variable is 10, the value of the function will be -3.

c) For what value of the independent variable will the value of the function be equal to 0.

y=0.3x−6

0=0.3x-6

6 = 0.3x

x = 6/0.3

x = 20

Therefore, if the independent variable is 20, the value of the function will be 0.

7 0
2 years ago
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