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shutvik [7]
3 years ago
6

Third derivative of xsinx?

Mathematics
1 answer:
Brut [27]3 years ago
6 0
Hello here is a solution :
f(x) = xsin(x)
f'(x) =( x)'sin(x) +x(sin(x))'
f'(x) = 1. sin(x)+x cos(x)
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Using decimal multipliers, it is found that the value of x is of 16.67.

<h3>What is a decimal multiplier?</h3>

Increases of a% or decreases of a% re represented by decimal values, as follows:

  • The equivalent multiplier for an increase of a% is given by: \frac{100 + a}{100}
  • The equivalent multiplier for an decrease of a% is given by: \frac{100 - a}{100}

In this problem:

  • The price at the beginning of January was of a.
  • Increase of 20% in January, hence 1.2a.
  • Decrease of 20% in February, hence 1.2(0.8)a.
  • Increase of 25% in March, hence 1.2(0.8)(1.25)a.
  • Decrease of x% in April, hence 1.2(0.8)(1.25)\left(\frac{100 - x}{100}\right)a

The price of gasoline at the end of April was the same as it had been at the beginning of January, hence:

a =1.2(0.8)(1.25)\left(\frac{100 - x}{100}\right)a

1.2\left(\frac{100 - x}{100}\right) = 1

\left(\frac{100 - x}{100}\right) = \frac{1}{1.2}

\frac{100 - x}{100} = 0.8333

100 - x = 83.33

x = 16.67

The value of x is of 16.67.

To learn more about decimal multipliers, you can take a look at brainly.com/question/24952336

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Step-by-step explanation:

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