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2 years ago

Third derivative of xsinx?

Mathematics

1 answer:

Brut [27]2 years ago

6 0

Hello here is a solution :
f(x) = xsin(x)
f'(x) =( x)'sin(x) +x(sin(x))'
f'(x) = 1. sin(x)+x cos(x)

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Solve.

Serggg [28]

Answer:

The solution is (4, 0)

Step-by-step explanation:

Using Linear combination method to solve:

$2d + e = 8\\d - e = 4\\$

Since "e" have the same coefficient in both equation with opposite operator; we will add.

$(2d + d) + (e - e) = (8 + 4)\\3d = 12\\$

Divide both side by coefficient of d which is 3

$\frac{3d}{3} = \frac{12}{3} \\d = 4\\$

Since d = 4; put 'd' into any of the equation to get 'e'

$2d + e = 8\\2(4) + e = 8\\8 + e = 8\\e = 8 - 8\\e = 0\\$

Therefore, the solution is (4, 0)

5 0

3 years ago

−−→ LO bisects ∠ NLM , LM = 18 , NO = 4 , and LN = 10 . LO → bisects ∠ NLM , LM = 18 , NO = 4 , and LN = 10 . What is the value

Sindrei [870]

Answer:

7.2

Step-by-step explanation:

Given that in triangle LMN, LO is angle bisector of angle L.

LN =10 and LM =18

By angle bisector theorem for triangles we have

LN/LM = NO/MO

Substitute the values for known things and x for MO

We get

10/18 = 4/x

Or cross multiply to get

10x=72

x=7.2

So answer is 7.2

3 0

3 years ago

A quantity P is an exponential function of time I, such that P = 160 when t = 6 and P = 150 when I = 4. Use the given informatio

Klio2033 [76]

Answer:

k = 0.032
P0 = 131.836

Step-by-step explanation:

Perhaps you want to use the points (t, P) = (4, 150) and (6, 160) to find the parameters P0 and k in the equation ...

$P(t)=P_0\cdot e^{kt}$

We know from the given points that we can write the equation as ...

$P(t)=150\left(\dfrac{160}{150}\right)^{(t-4)/(6-4)}=150\left(\dfrac{16}{15}\right)^{\frac{t}{2}-2}\\\\=150\left(\dfrac{16}{15}\right)^{-2}\times\left(\left(\dfrac{16}{15}\right)^{\frac{1}{2}}\right)^t$

Comparing this to the desired form, we see that ...

$P_0=150\left(\dfrac{16}{15}\right)^{-2}\approx 131.836\\\\e^{k}=\left(\dfrac{16}{15}\right)^{1/2}\rightarrow k=\dfrac{1}{2}(\ln{16}-\ln{15})\approx 0.0322693$

So, the approximate equation for P is ...

$P(t)=131.836\cdote^{0.032t}$

And the parameters of interest are ...

k = 0.032
P0 = 131.836

4 0

2 years ago

Solve the linear equation<br><br> <img src="https://tex.z-dn.net/?f=4%5E%7Bx%2B7%7D%20%3D%208%5E%7B2x-3%7D" id="TexFormula1" tit

GREYUIT [131]

Answer:

x = 5.75

Step-by-step explanation:

4^(x+7) = 8^(2x-3)

But; 4^(x+7) = 2^2(x+7)

8^(2x-3) = 2^3(2x-3)

2^2(x+7) = 2^3(2x-3)

Since the bases are the same;

2(x+7) = 3(2x-3)

2x + 14 = 6x -9

14 + 9 = 6x - 2x

23 = 4x

x = 23/4

<u>x = 5.75</u>

3 0

3 years ago

In an ice cream shop there is some money in a drawer. After 6 ice creams were sold, there were 70 euros left in the drawer. Afte

Verizon [17]

Answer: There were 40 euros in the drawer at the beginning.

Step-by-step explanation:

When we subtract 6 from 16, we get 10 more ice-creams were sold.

Similarly, we subtract 70 from 120, we get 50 euros was the total selling price of 10 ice-creams.

i.e. Selling price of 1 ice-cream = (50)÷10 =5 euros

Selling price of 6 ice-creams = 6 x 5 = 30 euros

Money in the drawer at the beginning = 70-30 = 40 euros

Hence, there were 40 euros in the drawer at the beginning.

7 0

2 years ago