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3 years ago

I WILL MARK YOU AS BRAINLIEST

Mathematics

1 answer:

Anna007 [38]3 years ago

3 0

Answer:

95 or more

Step-by-step explanation:

an average of 89 gives you a mean score of 445 to get an average of 90 he needs a 540 in total for all 6 exams that is a 95 or better.

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The main goal of a personal budget is to

Evgesh-ka [11]

Make sure you don't spend to much and have no more money left

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2 years ago

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6a2 + 8a - 25 = -3<br> Using the Quadratic Formula

drek231 [11]

Answer:

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6a^{2}+8a-25=-3

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Step-by-step explanation:

0/3

4 0

2 years ago

Write the recursive formula then determine the next term of 3,10,24,52

Schach [20]

Answer:

f[1] = 3
f[n] = 2·f[n-1] +4
108

Step-by-step explanation:

We observe that first differences of the given numbers are ...

10 -3 = 7

24 -10 = 14

52 -24 = 28

That is, each difference is 2× the previous one. This suggests an exponential relation that has a base of 2.

We notice that doubling a term doesn't give the next term, but gives a value that is 4 less than the next term. So, we can get the next term by doubling the previous one and adding 4.

Then our recursive relation is ...

f[1] = 3 . . . . the first term

f[n] = 2×f[n-1] +4 . . . . double the previous term and add 4

The next term is 2·52 +4 = 108.

7 0

3 years ago

The functions show two sisters' savings accounts and the

Crank

Answer:

Dana has a greater i risk value

Step-by-step explanation:

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3 years ago

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A square pyramid has a base with an area of 20 square meters, and its lateral faces have a slant height of x meters. Sydney is c

svetoff [14.1K]

1. Consider the pyramid ABCDE in the figure 1 attached:

Each side of the square base equals $\sqrt{20} = \sqrt{4*5} = \sqrt{4}* \sqrt{5}=2 \sqrt{5}$ (units)

Area of 1 lateral side of pyramid ABCDE is $\frac{1}{2}* 2 \sqrt{5}*x=\sqrt{5}x$

so the total lateral area is $4\sqrt{5}x$ (units squared)

and the total surface area is $20+4\sqrt{5}x$ (units squared)

2. Now consider the second figure KLMNP, Sydney's pyramid:

The lateral area is $4* \frac{1}{2}* 4 \sqrt{5} *2x=16 \sqrt{5}x$

so the total area of the second pyramid is $20+16 \sqrt{5}x$

So 2 things can be said about the areas:

i) the lateral area of Sydney's pyramid is $\frac{16 \sqrt{5}x}{4\sqrt{5}x} =4$ times larger than the lateral area of the original pyramid.

ii) The total area of Sydney's pyramid is $(20+16 \sqrt{5}x)-(20+4\sqrt{5}x)=12\sqrt{5}x$ units squared larger than the total area of the original pyramid.

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3 years ago

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