Discriminant D is given by:
D=b²-4ac
Implication of discriminant is as follows:
D<0 two zeros that are complex conjugate
D=0 one real zero of multiplicity 2
D>0 two distinct real zers
D= (+ve perfet square) two distinct rational zeros
From:
12x^2+10x+5=0
plugging in the equation we get:
10²-4×12×5
=100-240
=-140
thus
D<0
Answer is:
<span>A two irrational solutions </span>
Let the fist integer be x, the second is x+20
the product of the numbers is:
x(x+20)
the sum of the numbers is:
x+x+20=2x+20
the sum of the above operations will give us:
2x+20+x^2+20x=95
x^2+22x+20=95
this can be written as quadratic to be:
x^2+22x-75=0
solving the above we get:
x=3 and x=-25
but since the integers should be positive, then x=3
the second number is x+20=3+20=23
hence the numbers are:
3 and 23
Answer:
4
Step-by-step explanation:
The one that weighs the less is 80
<u><em>Pls give brainlest.</em></u>
Y=t(15)+4 Is what I think this word problem would be written in Slope-intercept form.