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Masteriza [31]
2 years ago
8

What is the GCF of 100 and 20

Mathematics
1 answer:
alexdok [17]2 years ago
4 0

Answer:

20

Step-by-step explanation:

20 is the GCF or greatest common factor of 20 and 100.

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PLEASE HELP. Prove that the value of the expression: b (36^5−6^9)(38^9−38^8) is divisible by 30 and 37.
pishuonlain [190]

Answer:

Step-by-step explanation:

First factor the second binomial

38^9 - 38^8 = 38^9 (38 - 1 ) = 38^9(37)

So there's your 37. This whole expression is divisible by 37

Now do the first  binomial

36^5 - (36^4)*6

36^4(36 - 6)

36^4(30) and there's your thirty.

That first term is going to cause a bit of trouble showing that 36^4 * 6 = 6^9

6(36^4) = 6(6^2)^4 = 6^1 * 6^8 = 6^9

So this factors into 30*(36^4)*37*38^9

3 0
3 years ago
Simplify 7.32a+2.1∙(2.7−18a)
tresset_1 [31]
7.32a + 2.1(2.7 -18a)
7.32a + 5.67 - 37.8a (multiply 2.1 to 2.7 and 18a)
5.67 - 30.48a (combine 7.32a and -37.8a since they are like terms)
6 0
3 years ago
PLEASE HELP ME
balandron [24]

9514 1404 393

Answer:

  • (3y)(2x^2 -1x -8xy +4y)
  • (3y)(x -4y)(2x -1)

Step-by-step explanation:

<u>Part A</u>: All of the coefficients have a common factor of 3. All of the variable products have a common factor of y, so the greatest common factor of all terms is 3y. The expression can be written as ...

  (3y)(2x^2 -1x -8xy +4y)

__

<u>Part B</u>: The remaining factor can be factored pairwise:

  3y(x(2x -1) -4y(2x -1)) = 3y(x -4y)(2x -1)

6 0
2 years ago
What percent is 25 is 4 plz help
andrew11 [14]

Answer: 16%

Step-by-step explanation:

4:25*100 =  

(4*100):25 =  

400:25 = 16

6 0
3 years ago
Solve the questions
Brilliant_brown [7]

Let's do the trig part first, then the calculus.  First we simplify the integrand.

\cot^3 x \sin ^3 x=\dfrac{\cos^3 x}{\sin^3 x} \sin^3 x= \cos^3 x

The triple angle formula is:

\cos 3x = 4 \cos^3 x - 3 \cos x

or

\cos^3 x = \frac 1 4 (\cos 3x + 3 \cos x)

Now we can integrate:

\displaystyle \int \cot^3 x \sin^3 x \ dx = \int \cos^3 x\ dx= \int \tfrac 1 4 (\cos 3x + 3 \cos x)\ dx

=\frac 1 4 (\frac 1 3 \sin 3x + 3 \sin x) + C

=\frac 1 {12} \sin 3x + \frac 3 4 \sin x + C



5 0
3 years ago
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