-- If the spinner is honest and the sections are all the same size, then
each section should have an equal chance of being landed on.
-- If there are 4 sections, then the chance of landing on each one
should be 1/4 or 25%.
-- The chance doesn't depend on how many times you try it.
If there are 4 sections, then each one should come up
25% of the time.
The value of x is 1.
The value of y is 4.
Solution:
Given TQRS is a rhombus.
<u>Property of rhombus:
</u>
Diagonals bisect each other.
In diagonal TR
⇒ 3x + 2 = y + 1
⇒ 3x – y = –1 – – – – (1)
In diagonal QS
⇒ x + 3 = y
⇒ x – y = –3 – – – – (2)
Solve (1) and (2) by subtracting
⇒ 3x – y – (x – y) = –1 – (–3)
⇒ 3x – y – x + y = –1 + 3
⇒ 2x = 2
⇒ x = 1
Substitute x = 1 in equation (2), we get
⇒ 1 – y = –3
⇒ –y = –3 – 1
⇒ –y = –4
⇒ y = 4
The value of x is 1.
The value of y is 4.
<h3>
Answer: 11/20</h3>
They got 33 heads out of 60 tosses, so,
33/60 = 11/20
You divide each part by 3 to reduce the fraction.
Step-by-step explanation:
- V= L×W×H
- you only need to know one side to figure out the
- volume of a cube
- volume is in 3Dimensions
- Multiple the sides in any order
- which side you call length, width, or height doesn't matter
that's how you find the answer.
does that help?
