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Line JK passes through points J(–3, 11) and K(1, –3). What is the equation of line JK in standard form?
2 answers:
Hello!
First of all we find the slope by dividing the difference of the y values by the difference of the x values as seen below.
The slope of our line is 7/2, or 3.5
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Now we will put the slope and a point on our line into slope intercept form and solve for b. We will use (-3,11).
11=3.5(-3)+b
11=10.5+b
b=0.5
Our final equation is shown below.
y=3.5x+0.5
I hope this helps!
First of all we find the slope by dividing the difference of the y values by the difference of the x values as seen below.
The slope of our line is 7/2, or 3.5
-------------------------------------------------------------
Now we will put the slope and a point on our line into slope intercept form and solve for b. We will use (-3,11).
11=3.5(-3)+b
11=10.5+b
b=0.5
Our final equation is shown below.
y=3.5x+0.5
I hope this helps!
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Answer:
43cm²
Step-by-step explanation:
let's first consider the area of a square.
the area is L² which means all sides are equal so we take the length times the breadth which is both equal because like we said all sides are equal.
so to find the side of the square using the area, we take the square root of both of the area.
and also
so we have the height of the triangle as 5cm and the base is 4.2cm.
now, from the triangle, since we have two sides and it's a right-angled, we can use Pythagoras' formula.
so the side 6.53cm is also the same side as the largest triangle. Since it's a square, all sides are equal. So we find the area of the largest triangle by using the formula
Area = L²
Area = 6.53²
Area = 42.6cm
the nearest cm square
Area = 43cm²