Given two points (x₁,y₁) and (x₂,y₂) the slope of the line that passes through these points will be:
m=(y₂-y₁)/(x₂-x₁)
In this case the points are: (a,2a) and (b,2b) and the slope would be:
m=(2b-2a)/(b-a)=2(b-a)/(b-a)=2
Answer; B.) 2
Yes you are right.
it is just still 5 I believe :P hope this helps
If we have the directrix at x = -3 (a vertical line) and the focus at (3, 0), then the vertex of the parabola is between these two, at the origin (0, 0). The parabola itself opens in the direction of the focus, which is to the right. The general equation for a parabola opening to the right is x^2 = 4cy, where c is the distance from the vertex to the focus (or to the directrix). In this case, c = 3 (from (0,0) to (3,0)). Therefore, the equation is x^2 = 12y, which is identical to y = (1/12)x^2, choice A.
Answer: The answer is y = 0.5x -3
Hope this helps, I can take the time to explain if needed:)