<u><em>Note:</em></u>
<em>Your question is a little unclear. But, from my understanding, I assume you may be asking the evaluation of the expression 36x - y when x = 3 and y = -6.</em>
<em>so I will solve based on my assumption which anyways would clear your concept.</em>
Answer:
The value of 36x - y when x = 3 and y = -6 will be: 114
Step-by-step explanation:
Given
Assuming the expression
36x - y
To Determine
Evaluate 36x - y when x = 3 and y = -6
Given the expression
substitute x = 3 and y = -6 to evaluate the expression
Therefore, the value of 36x - y when x = 3 and y = -6 will be: 114
The equation you want to use is this:
10x = 530 10 pages for x days
x = 530/10 530 pages divided by 10 pages
So the answer is,
53 days
Answer:
6x+21 (Maybe)
Are you doing the buddy method, how is your teacher wanting to do this, When you respond I might have the correct answer
(buddy method) Multiply the 2x and 7 by the 3 giving you 6x+21 and then that's it you cant do anything else but I don't know if that's how you're teacher wants it done.
Hi there, 1+1=2 and 4/7+4/7=8/7. Therefore, Mary and Fred ate 2 8/7 of the pie.
Answer:
1) (x + 3)(3x + 2)
2) x= +/-root6 - 1 by 5
Step-by-step explanation:
3x^2 + 11x + 6 = 0 (mid-term break)
using mid-term break
3x^2 + 9x + 2x + 6 = 0
factor out 3x from first pair and +2 from the second pair
3x(x + 3) + 2(x + 3)
factor out x+3
(x + 3)(3x + 2)
5x^2 + 2x = 1 (completing squares)
rearrange the equation
5x^2 + 2x - 1 = 0
divide both sides by 5 to cancel out the 5 of first term
5x^2/5 + 2x/5 - 1/5 = 0/5
x^2 + 2x/5 - 1/5 = 0
rearranging the equation to gain a+b=c form
x^2 + 2x/5 = 1/5
adding (1/5)^2 on both sides
x^2 + 2x/5 + (1/5)^2 = 1/5 + (1/5)^2
(x + 1/5)^2 = 1/5 + 1/25
(x + 1/5)^2 = 5 + 1 by 25
(x + 1/5)^2 = 6/25
taking square root on both sides
root(x + 1/5)^2 = +/- root(6/25)
x + 1/5 = +/- root6 /5
shifting 1/5 on the other side
x = +/- root6 /5 - 1/5
x = +/- root6 - 1 by 5
x = + root6 - 1 by 5 or x= - root6 - 1 by 5
