All categories

3 years ago

4.9 g = kg convert answer it plz

Mathematics

2 answers:

laiz [17]3 years ago

8 0

Answer:

0.0049

Step-by-step explanation:

pishuonlain [190]3 years ago

4 0

ANSWER

$4.9g = 0.0049kg.$

EXPLANATION

We want to convert 4.9 grams to kilograms.

Recall that:

1000 grams makes 1 kilograms.

To convert from grams to kilograms, we divode by 1000.

This implies that;

$4.9g= \frac{4.9}{1000} kg$

$4.9g = 0.0049kg$

You might be interested in

"!I NEED HELP WITH MY MATH PROBLEMS, PLEASE!" (27 POINTS)

Len [333]

25. yes it's direct variation
26. yes

5 0

3 years ago

Read 2 more answers

if 6 people share 990 grams of cookie but each leave behind 27 grams how much grams did each person eat

evablogger [386]

Answer: 276 grams.

Step-by-step explanation:

7 0

2 years ago

What is the measure of ∠DAB? Enter your answer in the box. ° quadrilateral a b c d with side a b parallel to side b c and side a

charle [14.2K]

Answer: The measure of angle ∠DAB is 84

Step-by-step explanation:

Step 1: 96 + 96 = 192

Step 2: 360 - 192 = 168

Step 3: 168 / 2 = 84

7 0

4 years ago

Read 2 more answers

The Y-intercept (b0) represents the a. variation around the sample regression line. b. change in estimated Y per unit change in

inn [45]

Answer: I don’t honestly know. I just need points

Explanation:

3 0

3 years ago

Need help please its Calculus. Ill give the 5 stars as well.

algol13

Answer:

$\displaystyle y = 2e^\bigg{\frac{x^3}{3}} + 1$

General Formulas and Concepts:

Pre-Algebra

Order of Operations
Equality Properties

Algebra I

Functions
Function Notation
Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$

Algebra II

Natural logarithms ln and Euler's number e

Calculus

Derivatives

Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Slope Fields

Separation of Variables

Solving Differentials

Integrals

Antiderivatives

Integration Constant C

Integration Rule [Reverse Power Rule]: $\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Property [Addition/Subtraction]: $\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx$

U-Substitution

Logarithmic Integration: $\displaystyle \int {\frac{1}{u}} \, dx = ln|u| + C$

Step-by-step explanation:

*Note:

When solving differential equations in slope fields, disregard the integration constant C for variable y.

Step 1: Define

$\displaystyle \frac{dy}{dx} = x^2(y - 1)$

$\displaystyle f(0) = 3$

Step 2: Rewrite

Separation of Variables. Get differential equation to a form where we can integrate both sides and rewrite Leibniz Notation.

[Separation of Variables] Rewrite Leibniz Notation: $\displaystyle dy = x^2(y - 1) \ dx$
[Separation of Variables] Isolate y's together: $\displaystyle \frac{1}{y - 1} \ dy = x^2 \ dx$

Step 3: Find General Solution Pt. 1

[Differential] Integrate both sides: $\displaystyle \int {\frac{1}{y - 1}} \, dy = \int {x^2} \, dx$
[dx Integral] Integrate [Integration Rule - Reverse Power Rule]: $\displaystyle \int {\frac{1}{y - 1}} \, dy = \frac{x^3}{3} + C$

Step 4: Find General Solution Pt. 2

Identify variables for u-substitution for dy.

Set: $\displaystyle u = y - 1$
Differentiate [Basic Power Rule]: $\displaystyle du = dy$

Step 5: Find General Solution Pt. 3

[dy Integral] U-Substitution: $\displaystyle \int {\frac{1}{u}} \, du = \frac{x^3}{3} + C$
[dy Integral] Integrate [Logarithmic Integration]: $\displaystyle ln|u| = \frac{x^3}{3} + C$
[Equality Property] e both sides: $\displaystyle e^\bigg{ln|u|} = e^\bigg{\frac{x^3}{3} + C}$
Simplify: $\displaystyle |u| = Ce^\bigg{\frac{x^3}{3}}$
Rewrite: $\displaystyle u = \pm Ce^\bigg{\frac{x^3}{3}}$
Back-Substitute: $\displaystyle y - 1 = \pm Ce^\bigg{\frac{x^3}{3}}$
[Equality Property] Isolate y: $\displaystyle y = \pm Ce^\bigg{\frac{x^3}{3}} + 1$

General Form: $\displaystyle y = \pm Ce^\bigg{\frac{x^3}{3}} + 1$

Step 6: Find Particular Solution

Substitute in function values [General Form]: $\displaystyle 3 = \pm Ce^\bigg{\frac{0^3}{3}} + 1$
Simplify: $\displaystyle 3 = \pm C + 1$
[Equality Property] Isolate C: $\displaystyle 2 = \pm C$
Rewrite: $\displaystyle C = 2$
Substitute in C [General Form]: $\displaystyle y = 2e^\bigg{\frac{x^3}{3}} + 1$

∴ our particular solution is $\displaystyle y = 2e^\bigg{\frac{x^3}{3}} + 1$ .

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentials and Slope Fields

Book: College Calculus 10e

6 0

3 years ago