The number of adults at the middle school dance is equal to the number of students

Find the product (8/6n-4)(9n^2-4)

Leokris [45]

Answer:

4(3n+2) or 12n+8

Step-by-step explanation:

Given expression is:

$(\frac{8}{6n-4})(9n^{2}-4)$

The numerator of the fraction will be multiplied with 9n^2- 4

So, Multiplication will give us:

$=\frac{8(9n^2-4)}{6n-4}$

We can simplify the expression before multiplication.

The numerator will be broken down using the formula:

$a^2 - b^2 = (a+b)(a-b)\\So,\\= \frac{8[(3n)^2 - (2)^2]}{6n-4}\\ = \frac{8(3n-2)(3n+2)}{6n-4}$

We can take 2 as common factor from denominator

$=\frac{8(3n-2)(3n+2)}{2(3n-2)}\\After\ cutting\\= 4(3n+2)$

Hence the product is 4(3n+2) or 12n+8 ..

6 0

3 years ago

Find the next two terms for the following pattern 1, -2, 2, -4, 0

Oxana [17]

After figuring out a common difference in this pattern, we can get further terms in the pattern:
1, -2, 2, -4, 0, -3, -1

5 0

2 years ago

In the figure below, if angle ZYX measures 23 degrees, then arc XY measures 45 degrees.

ollegr [7]

Answer:

FALSE

Step-by-step explanation:

Assuming ZY is a tangent, the measure of the arc will be twice the measure of the angle. If the angle ZYX is 23°, the measure of arc YX will be 46°.

4 0

3 years ago

If the number of Conference participants decreases by 20% compared to last year, there would be 1760 participants this year. If

Basile [38]

2,640 this year
2,112 last year

the 1760 is 20% less than - so 120% of 1760 is the previous year:
1760 * 1.2 = 2112

2112 increased by 25% is a total of 125%:
2112 *1.25 = 2640

7 0

3 years ago

Read 2 more answers

A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as

Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let X = number of seconds in the batch.

The probability of the random variable X is, p = 0.31.

The random variable X follows a Binomial distribution with parameters n and p.

The probability mass function of X is:

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...$

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

$P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888$

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

$=1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776$

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

$={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453$

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0

3 years ago