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IgorC [24]
3 years ago
14

Please answer the six questions in the picture please

Mathematics
2 answers:
lisov135 [29]3 years ago
6 0
Y=mx+b
m=slope
b=y itnercept
remember the points go in (x,y) form
also, an easy way to find points is to subsitute values for x andn get values for y

so
6. y=5x-1
 some points are (0,-1) (1,4) (2,9) (314)

7. y=-x+8
some points are (0,8) (1,7) (2,6) (3,5)

8. y=0.2x+.3
somepoints are (0,0.3) (1,0.5) (2,0.7) (3,0.9)

9. y=1.5x-3
somepoints are (0,-3) (1,-1.5) (2,0) (3,1.5)

10. y=-1/2x+4
somepoints are (0,4) (1,7/2) (2,3) (3,5/2)

11. y=2/3x-5
some points are (0,-5) (1,-13/3) (2,-11/3) (3,-3)
Levart [38]3 years ago
3 0
6.  (0 , -1) ; (1, 4) ; ( 2, 9) ; (3, 14 ) ; ( 4 , 19 )

7. ( 0 , 8 ) ; ( 1 , 7 ) ; (2  , 6 ) ; ( 3 , 5 ) 

8. ( 0 , 0. 3  ) ; ( 1 , 0.5 ) ; ( 2 , 0.7 ) ; ( 3 , 0.9 ) 

9. (0 , -3) ;  ( 1, -1.5) ; (2, 0) ; (3, 1.5)
 
10. ( 0, 4) ; (1, 3.5) ; (2, 3) ; (3, 2.5)

11. (0, -5) ; (3, -3) ; (6, -1) ; (12, 3)

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A television game has 6 shows doors, of which the contests must pick 2. behind two of the doors are expensive cars, and behind t
Katyanochek1 [597]
The answer to this question:
One car probability 82/120
No car probability = 24/120
At least one car probability= 96/120

I will focus answering the 3 doors probability since the 2nd door problem is solved in the previous problem. (brainly.com/question/5761449)

No car condition
1. 1st door consolation, 2nd door consolation=, 3rd door consolation= 4/6 * 3/5 * 2/4= 24/120
This was also can be found by: (4!/1!)/ (6!/3!) = 24/120

(At least one car probability)  is the opposite of (no car probability) In this case, the easier way is 
100% - (no car probability) = 120/120 - 24/120= 96/120

One car probability is (At least one car probability) - (2 car probability). It will be easier to count the 2 car probability and subtract the (At least one car probability) 
Two car condition:
1. 1st door car, 2nd door car, 3rd door consolation = 2/6 * 1/5 * 4/4 =8/ 120
2.1st door car, 2nd door consolation, 3rd door car =2/6 * 4/5 * 1/4 = 8/120
3. 1st door consolation, 2nd door car, 3rd door car= 4/6 * 2/5 * 1/4= 8/120
The total probability will be 8/120+ 8/120 + /120= 24/120
This was also can be found by: (2!) (4!/2!)/ (6!/3!) = 24/120

One car probability =  (At least one car probability) - (2 car probability)= 96/120-24/120= 82/120
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3 years ago
If you help me I’ll mark brainliest
Dafna11 [192]

Answer:

1= 2x+74

or,

or,

or

now,

1+3= being straight angle

5 0
3 years ago
Solve for g. C = d/g
icang [17]

Answer:

I believe that g=dc

Step-by-step explanation:

You swap positions with g and c along with their sign of operation.

7 0
3 years ago
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