All categories

3 years ago

Sean said that the slope of the line is 3. is he correct?

Mathematics

2 answers:

xeze [42]3 years ago

8 0

What does the line look like?

krok68 [10]3 years ago

5 0

Answer:

yes

Step-by-step explanation:

You might be interested in

3/5 -(-2/7) i need the value of the expression and work to show

trapecia [35]

The answer is 31/35 :)

7 0

3 years ago

A local park is in the shape of a square. A map of the local park is made with the scale 1 inch to 200 feet. If a straight path

kkurt [141]

Answer:

600 ft per side

Step-by-step explanation:

1 in = 200 feet

12 in = 1 foot

12 in * 200 ft= 2400 ft

2400/4 = 600 ft per side

5 0

2 years ago

I need help doing thsi

Naily [24]

True! Because T is the defining letter of the line, so it would be true!

Hope this helps!! :)

7 0

3 years ago

Question 1 (Essay Worth 10 points) (01.02 MC) Part A: If (26)x = 1, what is the value of x? Explain your answer. (5 points) Part

katen-ka-za [31]

Answer:

See Explanation

Step-by-step explanation:

The question is not clear. However, I will treat the question as:

$(26)x = 1$

$(50)x = 1$

and:

$(2^6)^x = 1$

$(5^0)^x = 1$

Solving: $(26)x = 1$ and $(50)x = 1$

$(26)x = 1$

Divide both sides by 26

$x = \frac{1}{26}$

$(50)x = 1$

Divide both sides by 50

$x = \frac{1}{50}$

Solving $(2^6)^x = 1$ and $(5^0)^x = 1$

$(2^6)^x = 1$

Express 1 as 2^0

$(2^6)^x = 2^0$

Remove bracket

$2^{6x} = 2^0$

Cancel out 2

$6x = 0$

Divide both sides by 6

$x = \frac{0}{6}$

$x = 0$

$(5^0)^x = 1$

Express 1 as 5^0

$(5^0)^x = 5^0$

Cancel out 5^0

$x = 1$

8 0

3 years ago

Find f(-1) if f(x) = -3x - 5 Choices A. -9 B. -8 C. -2 D. 2

GenaCL600 [577]

Answer:

Step-by-step explanation:

All you have to do is plug in -1 for x in the equation

f(-1)= -3(-1)-5

-3 times -1 = 3

Then you need to subtract 5 leaving it to be 3-5 = -2

Therefore the answer is C. - 2

5 0

3 years ago

Read 2 more answers

Sean said that the slope of the line is 3. is he correct?​

Sean said that the slope of the line is 3. is he correct?