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3 years ago

1. Two forces are applied to a box on a frictionless surface. One force is 40 N [S]. The second

Physics

1 answer:

irinina [24]3 years ago

3 0

The overall net force is 40.6 N [N59.5 °W]

Explanation:

Net force in x direction

F_x = 70 cos 30° - 40 = 20.62 N

Net force in y direction

F_y = 70 sin 30° = 35N

The resultant of two forces is

R = $\sqrt{F _x^2 +F _y^2}$

= $\sqrt{20.62^2 + 35^2}$

=40.6 N

The direction of resultant is

θ= tan ^-1 ( $\frac{35}{20.62}$

θ=59.5 ° (N59.5 W)

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$m\frac{v^2}{(R+h)}=\frac{GMm}{(R+h)^2}$

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The escape speed of an object from the surface of a planet/asteroid is given by

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