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anzhelika [568]
3 years ago
11

a train has an initial velocity of 44 metre per second and an acceleration of 4 metre per second square. its velocity after 10 s

econds is​
Physics
1 answer:
sesenic [268]3 years ago
6 0

Answer:

v = 84m/s

Explanation:

acceleration = change in velocity / time

a = v -u / t

v = ? , u = 44m/s , t = 10s, a = 4m/s²

a = v - u / t

4 = v - 44 / 10

Cross multiply

v - 44 = 40

v = 44 + 40

v = 84m/s

I hope this was helpful, please rate as brainliest

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eimsori [14]

Answer:

\alpha = 0.305 rad/s^2

Explanation:

initial frequency of revolution is given as

f_1 = 100/3 rpm

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\omega_i = 2\pi(\frac{100}{3\times 60})

\omega_i = 3.49 rad/s

Similarly final angular speed is given as

\omega_f = 2\pi f_2

\omega_f = 2\pi(\frac{45}{60})

\omega_f = 4.71 rad/s

Now angular acceleration is given as

\alpha = \frac{\omega_f - \omega_i}{\Delta t}

\alpha = \frac{4.71 - 3.49}{4}

\alpha = 0.305 rad/s^2

3 0
3 years ago
Which is best supported by the data in the chart?
bija089 [108]

Answer:

Option C: Current X has a lower potential difference than Current Y.

Explanation:

The chart above only shows the potential difference of difference current.

A careful observation of the chart shows that Current X has a lower potential difference than Current Y.

7 0
3 years ago
describe two methods a researcher can use to avoid obtaining a nonrepresentative sample this is for high school psychology
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Take a purely random sample or to deliberately pick individuals who represents the various groups
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Ice skaters often end their performances with spin turns, where they spin very fast about their center of mass with their arms f
vampirchik [111]

Answer:

\large \boxed{\text{30 rev/s}}

Explanation:

This question is based on the Law of Conservation of Angular Momentum.

Angular momentum (L) equals the moment of inertia (I) times the angular speed (ω).

L = Iω

If momentum is conserved,

I₁ω₁ = I₂ω₂

Data:

 I₁ = 3.5    kg·m²s⁻¹

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Calculation:

\begin{array}{rcl}I_{1}\omega_{1} &= &I_{2}\omega_{2}\\\text{3.5 kg$\cdot$m$^{2}$}\times \text{6.0 rev/s} &= &\text{0.70 kg$\cdot$m$^{2}$}\times\omega_{2}\\\text{21 rev/s} &= &0.70\omega_{2}\\\omega_{2} & = & \dfrac{\text{21 rev/s}}{0.70}\\\\&=&\textbf{30 rev/s}\\\end{array}\\\text{The skater's final rotational speed is $\large \boxed{\textbf{30 rev/s}}$}

8 0
4 years ago
How do you find the velocity after a collision
Evgen [1.6K]

Answer:

In a collision, the velocity change is always computed by subtracting the initial velocity value from the final velocity value. If an object is moving in one direction before a collision and rebounds or somehow changes direction, then its velocity after the collision has the opposite direction as before.

Explanation:

7 0
4 years ago
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