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NeX [460]
3 years ago
7

Which of the following is NOT considered a branch of Chemistry?

Chemistry
2 answers:
zimovet [89]3 years ago
8 0

Answer:

pure chemistry

4

Explanation:

It is the consideration of the facts and theories of chemistry in their purely scientific relations. Therefore it is not considered to be a branch of chemistry because it doesn't necessarily refer to their practical application or mere utility.

mestny [16]3 years ago
4 0

Answer:

Pure Chemistry -- is NOT considered a branch of Chemistry.

Explanation:

Second question is number 4.

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Darin skateboarded to the north at 4 m/s. In 5 seconds, he sped up to 7 m/s. What was his acceleration?
Julli [10]
To solve this problem we can use following equation.

v =u + at

Where v is the final velocity (m/s), u is the initial velocity (m/s), a is the acceleration (m/s²) and t is the time taken (s).

v = 7 m/s
u = 4 m/s
a = ?
t = 5 s

By applying the equation, we can get
    7 m/s = 4 m/s + a x 5 s
    3 m/s = a x 5 s
          a = 0.6 m/s²

Hence, the acceleration is 0.6 m/s² towards north.

Answer is "C".
4 0
3 years ago
How many grams of ammonia (NH3) are produced when you react 4.76 grams of hydrogen (H2)
Andrews [41]

Answer: hre

Explanation:

N2(g) + 3H2-> 2NH3(g)  This is the balanced equation

Note the mole ratio between N2, H2 and NH3.  It is 1 : 3 : 2  This will be important.

 

moles N2 present = 28.0 g N2 x 1 mole N2/28 g = 1 mole N2 present

moles H2 present = 25.0 g H2 x 1 mole H2/2 g = 12.5 moles H2 present

Based on mole ratio, N2 is limiting in this situation because there is more than enough H2 but not enough N2.

 

moles NH3 that can be produced = 1 mole N2 x 2 moles NH3/mole N2 = 2 moles NH3 can be produced  

grams of NH3 that can be produced = 2 moles NH3 x 17 g/mole = 34 grams of NH3 can be produced

 

NOTE:  The key to this problem is recognizing that N2 is limiting, and therefore limits how much NH3 can be produced.

6 0
4 years ago
Read 2 more answers
Can u help me we promise u that we will follow u
Elena L [17]

B, water and ice are the main causes .

3 0
3 years ago
Gold forms a substitutional solid solution with silver. Compute the number of gold atoms per cubic centimeter for a silver-gold
Sonja [21]

Answer:

The Number of gold atoms are =N_{Au}=1.81718*10^{22}\ atoms/cm^3

Explanation:

The formula we are going to use is:

N_{Au}=\frac{N_A*C_{Au}}{{\frac{C_{Au}A_{Au} }{\rho_{Au}}}+\frac{A_{Au}}{\rho_{Ag}}(100-C_{Au})}

Where:

N_{Au} are number of gold atoms.

N_A is Avogadro Number.

C_{Au} is the amount of gold.

A_{Au} is the atomic weight of gold.

\rho_{Au} is the density of gold.

\rho_{Ag} is the density of silver.

C_{Ag} is the amount of silver.

N_{Au}=\frac{6.023*10^{23}*45\%wt}{\frac{45\%wt*196.97}{19.32}+\frac{196.97}{10.49}(100-45\%wt)}\\ N_{Au}=1.81718*10^{22}\ atoms/cm^3

The Number of gold atoms are =N_{Au}=1.81718*10^{22}\ atoms/cm^3

5 0
3 years ago
Convert 512 kilograms to milligrams.<br><br> 0.000512<br> 0.512<br> 512,000<br> 512,000,000
olga55 [171]
The answer is D! 512000000
5 0
4 years ago
Read 2 more answers
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