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3241004551 [841]
3 years ago
11

Liquid water in the earth's air is an example of a solution. What type of solution would it be?

Chemistry
1 answer:
monitta3 years ago
6 0
I dont really understand the question very well but it could be evaporation ?
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Along with subduction, what other process changes sedimentary rocks to metamorphic rocks?
muminat
It would be weathering because of all the heat and pressure.
7 0
3 years ago
Why is glass brittle
WITCHER [35]
Glass doesn't contain planes of atoms that can slip past each other, so there is no way to relieve stress. It has many microscopic cracks that act as seeds for fracture. It’s molecular structure is composed of tetrahedral crystals so it ruptured easily under stress
6 0
3 years ago
Calculate the molarity of a solution prepared by
lions [1.4K]

Answer:

Molarity= 0.414M

Explanation:

Applying dilution formula

C1V1=C2V2

0.9×0.575= C2× 1.25

C2= 0.414M

4 0
3 years ago
What mass of water could be warmed from 21.4 degrees celsius to 43.4 degrees celsius by the pellet dropped inside it? Heat capac
Artist 52 [7]

42.34 g of water could be warmed from 21.4°C to 43.4°C  by the pellet dropped inside it

Heat loss by the pellet is equal to the Heat gained by the water.

q_{w} = -q_{p} ….(1)

where, q_{w} is the heat gained by water

q_{p} is the heat loss by pellet

q_{w} = mCΔT

where m = mass of water

C = specific heat capacity of water = 4.184 J/g-°C

ΔT = Increase in temperature

ΔT for water = 43.4 - 21.4 = 22°C

q_{w} = m × 4.184 × 22 …. (2)

Now

q_{p} = H_{c} ×ΔT

where H_{c} = Heat capacity of pellet = 56J/°C

Δ T for pellet = 43.4 - 113 =- 69.6°C

q_{p} = 56 × -69.6 = -3897.6 J

From equation (1) and (2)

-m× 4.184 × 22 =-3897.6

m= 42.34 g

Hence, 42.34 g of water could be warmed from 21.4 degrees Celsius to 43.4 degrees Celsius by the pellet dropped inside it.

Learn more about specific heat here brainly.com/question/16559442

#SPJ1

6 0
2 years ago
A hydrocarbon, containing only C and H, can react with excess oxygen gas to produce carbon dioxide and water. The result of the
Tcecarenko [31]
I believe the answer you are looking for would be HC

5 0
3 years ago
Read 2 more answers
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