A student listed three ways to predict if a bond is ionic.

1 answer:

4 0

1 and 3 only because metal are easily to loss electron while non metal are difficult to loss electron that's why it called heavy elements.

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Determine how many carbon dioxide (CO2) molecules are produced if 8.45 x 1023 molecules of water (H2O) are produced 2 C2H6 (g) +

Andreas93 [3]

Ill get back to you on this

5 0

2 years ago

A person with a body temperature of 37°C holds an ice cube with a temperature of 0°C in a room where the air temperature is 20.°

Arlecino [84]

The answer is (2). Heat always flows down the temperature gradient, from high temperature to low temperature. Therefore, since the person is the warmest, heat flows from the person to both the ice and the air. Additionally, since the air is warmer than the ice, heat flows from the air to the ice.

8 0

3 years ago

Consider the reaction 2 al + Fe2O3 to 2Fe + Al2O3. If 60.0g of Al is reacted with excess Fe2O3, determine the amount (in moles)

olganol [36]

The amount of Al2O3 in moles= 1.11 moles while in grams = 113.22 grams

calculation

2 Al + Fe2O3 → 2Fe + Al2O3

step 1: find the moles of Al by use of moles= mass/molar mass formula

= 60.0/27= 2.22 moles

Step 2: use the mole ratio to determine the moles of Al2O3.

The mole ratio of Al : Al2O3 is 2: 1 therefore the moles of Al2O3= 2.22/2=1.11 moles

Step 3: finds the mass of Al2O3 by us of mass= moles x molar mass formula.

The molar mass of Al2O3 = (2x27) +( 16 x3) = 102 g/mol

mass is therefore= 102 g/mol x 1.11= 113.22 grams

7 0

3 years ago

how many grams of oxygen gas are needed to produce 10.0 grams of carbon dioxide according to the balanced equation of CH4

Alinara [238K]

Molar mass of :

O2 = 16 * 2 = 32 g/mol

CO2 = 12 + 16 * 2 = 44 g/mol

Balanced chemical equation :

1 CH4 + 2 O2 = 1 CO2 + 2 H2O
↓ ↓
2 moles 1 mole

2* 32 g O2 ----------> 1* 44 g CO2
x g O2 ------------> 10.0 g CO2

44 x = 2 * 32*10.0

44 x = 640

$x = \frac{640}{44}$

$x = 14.54 g$ of O2

7 0

3 years ago

Describe the appropriate way to smell an unknown substance in the lab.

Gnom [1K]

Answer:

smelling it without glasses or putting your face/nose really close to the substance

Explanation:

4 0

3 years ago

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