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3 years ago

In triangle PQR if angle P=60° and angle Q=50° then the largest side of a triangle is ?

Mathematics

1 answer:

Citrus2011 [14]3 years ago

5 0

Answer:

Step-by-step explanation:

∠R = 180 - ( 60 + 50) = 180 -110 = 70

So, the largest side is opposite side of ∠R, so it is PQ

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Answer with Step-by-step explanation:

We are given that

P(A)=0.4 and P(B)=0.7

We know that

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We know that

Maximum value of $P(A\cup B)$ =1 and minimum value of $P(A\cup B)$ =0

$0\leq P(A\cup B )\leq 1$

$0\leq P(A)+P(B)-P(A\cap B)\leq 1$

$0\leq 0.4+0.7-P(A\cap B)\leq 1$

$0\leq 1.1-P(A\cap B)\leq 1$

$0\leq 1.1-P(A\cap B)$

$P(A\cap B)\leq 1.1$

It is not possible that $P(A\cap B)$ is equal to 1.1

$1.1-P(A\cap B)\leq 1$

$-P(A\cap B)\leq 1-1.1=-0.1$

Multiply by (-1) on both sides

$P(A\cap B)\geq 0.1$

Again, $P(A\cup B)\geq P(B)$

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$1.1-P(A\cap B)\geq 0.7$

$-P(A\cap B)\geq -1.1+0.7=-0.4$

Multiply by (-1) on both sides

$P(A\cap B)\leq 0.4$

Hence, $0.1\leq P(A\cap B)\leq 0.4$

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In triangle PQR if angle P=60° and angle Q=50° then the largest side of a triangle is ?​

In triangle PQR if angle P=60° and angle Q=50° then the largest side of a triangle is ?