3 years ago

How do you solve log base 64 of 0.5 = x?

1 answer:

4 0

㏒₆₄(0.5) = x
  64ˣ = 0.5
  ㏑(64ˣ) = ㏑(0.5)
x㏑(64) = ㏑(0.5)
  x㏑(2⁶) = ㏑(2⁻¹)
6x㏑(2) = -㏑(2)
6㏑(2) 6㏑(2)
x = ⁻¹/₆

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