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poizon [28]
3 years ago
15

How do you solve log base 64 of 0.5 = x?

Mathematics
1 answer:
alexandr1967 [171]3 years ago
4 0
㏒₆₄(0.5) = x
        64ˣ = 0.5
  ㏑(64ˣ) = ㏑(0.5)
 x㏑(64) = ㏑(0.5)
  x㏑(2⁶) = ㏑(2⁻¹)
 6x㏑(2) = -㏑(2)
  6㏑(2)     6㏑(2)
           x = ⁻¹/₆
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