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2 years ago

What did I do wrong here?

Mathematics

1 answer:

photoshop1234 [79]2 years ago

7 0

Answer:

You put 8i^2 instead of 12i^2. You multiply -6i by -2i which equal -12i^2

Step-by-step explanation:

-7 + 6i - 14i+ 12i^2

-7 - 8i - 12

-19 - 8i

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Divide to find two equivalent fraction 4/12

SCORPION-xisa [38]

Answer: 2/6 and 1/3

Step-by-step explanation: Equivalent fractions are fractions that have the same value but have different top and bottom numbers.

We can find 1 equivalent fraction by dividing the numerator and the denominator by 2 and we get 2/6. We can also reduce 2/6 by dividing the numerator and the denominator by 2 and we get 1/3.

So two equivalent fractions for 4/12 would be 2/6 and 1/3.

4 0

3 years ago

Please help me for brainiest):):):):):):

bazaltina [42]

Answer:

You can find 0.5% of a number by multiplying the number by

Step-by-step explanation:

3 0

2 years ago

Surface area???????????

MAVERICK [17]

Answer:

The option B is the correct answer. 79.18 m²

Step-by-step explanation:

Surface area = Base area + Lateral surface area

Area of triangle = bh/2

b - base and h - height

To find the base area

We can consider the base is a hexagon.

A regular hexagon is a combination of 6 equilateral triangle

Base area = 6 * area of triangle

base b = 3

To find the height

h =√[(6.2)² - (5.6)₂] = 2.7

Area of triangle bh/2 = (3 * 2.7)/2 = 3.99

Area of base = 23.95

To find lateral surface area

Lateral surface area = 6 * area of triangle

Area of triangle = bh/2 =(3 *6.2)/2 = 9.3

Lateral surface area = 6 * 9.3 = 55.8

To find the total surface area 

Total surface area = Base area + lateral surface area = 23.95 + 55.8

= 79.75 m²

Therefore the option B is the correct answer. 79.18 m²

7 0

2 years ago

Two different simple random samples are drawn from two different populations. The first sample consists of 30 people with 16 hav

Furkat [3]

Answer:

There is no significant evidence that p1 is different than p2 at 0.01 significance level.

99% confidence interval for p1-p2 is -0.171 ±0.237 that is (−0.408, 0.066)

Step-by-step explanation:

Let p1 be the proportion of the common attribute in population1

And p2 be the proportion of the same common attribute in population2

$H_{0}$ : p1-p2=0

$H_{a}$ : p1-p2≠0

Test statistic can be found using the equation:

$z=\frac{p2-p1}{\sqrt{{p*(1-p)*(\frac{1}{n1} +\frac{1}{n2}) }}}$ where

p1 is the sample proportion of the common attribute in population1 ( $\frac{16}{30} =0.533$ )

p2 is the sample proportion of the common attribute in population2 ( $\frac{1337}{1900} =0.704$ )

p is the pool proportion of p1 and p2 ( $\frac{16+1337}{30+1900}=0.701$ )

n1 is the sample size of the people from population1 (30)

n2 is the sample size of the people from population2 (1900)

Then $z=\frac{0.704-0.533}{\sqrt{{0.701*0.299*(\frac{1}{30} +\frac{1}{1900}) }}}$ ≈ 2.03

p-value of the test statistic is 0.042>0.01, therefore we fail to reject the null hypothesis. There is no significant evidence that p1 is different than p2.

99% confidence interval estimate for p1-p2 can be calculated using the equation

p1-p2± $z*\sqrt{\frac{p1*(1-p1)}{n1}+\frac{p2*(1-p2)}{n2}}$ where