Are you asking what the answer is because you are not asking us anything. I would really like to help you out but I need to know what the question is first.
Answer:
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Let's translate the words into expressions:
11 less than 7 times a number is ![7x-11](https://tex.z-dn.net/?f=%207x-11%20)
5 more than 6 times the number is ![6x+5](https://tex.z-dn.net/?f=%206x%2B5%20)
So we have the equation
![7x-11 = 6x+5](https://tex.z-dn.net/?f=%207x-11%20%3D%206x%2B5%20)
Subtract 6x from both sides:
![x - 11 = 5](https://tex.z-dn.net/?f=%20x%20-%2011%20%3D%205%20)
Add 11 to both sides:
![x=16](https://tex.z-dn.net/?f=%20x%3D16%20)
Quadrant II.
Hope this helps.
The formula for the total sum of the inner angles of the polygon is
Sn= (n-2) 180°
1) S6= (6-2) 180 = 4*180 = 720° In the hexagon all angles are equal
α= S6/6= 720/6= 120°
2) In each polygon the sum of the external angles is 360°
3) S5= (5-2) 180 = 540° than we can add up all angles
x+131+108+107+110=540 => x= 540-456= 84°
4) α = 360/5=72°
Good luck!!!